Jump to content
Electronics-Lab.com Community

zulcao

Members
  • Posts

    14
  • Joined

  • Last visited

    Never

zulcao's Achievements

Newbie

Newbie (1/14)

0

Reputation

  1. Well, one will probably work, but gets VERY hot and needs a huge heatsink (with fans).
  2. Recently I got an 1000va :o by 24v, will work ?
  3. once more, RV3 is to set the maximum current to 3 or 5 amps (one way to set: short the PSU, adjust P2 (amp) to max, adjust the RV3 to desired maximum current, be quick, the transistor will get HOT). RV2 is to set the maximum voltage to 30v (how to set: in open circuit adjust the P1 (volts) to max, adjust the RV2 to be 30v at the terminals of the PSU). RV1 is to set the ZERO voltage (how to set: in open circuit adjust the P1 (volts) to min, adjust the RV1 to be 0v at the terminals of the PSU).
  4. The D12 led only light up when the current passing by R7 is over the limit set by P2 (U3). In which circumstances the wire burned up ?
  5. So if you join the both comon, when you out put them in series, it will short. :o
  6. if you DONT put Them in series, I think ther isnt any problem
  7. Thanks for your help, it was very useful. I really was lucky because the PSU is working ;D. But as soon as I can I'll change for the MC34071. Thank you very much
  8. I made these changes and seems to be working ;D ;D ;D Obs: OAmp: UA741
  9. I used the UA741. With the tension he'd never zero, so I put a third diode to the negative input is -2.1 V and also linked to the negative pin of u2, This worked perfectly for the tension, but not to the current, I was wondering if u3 can put a negative output? let say -0.7 V? this could solve the problem I think.
  10. well, I do not know if it's because I changed the oamp, i have not found anyone here in Brazil, but still have a 0.6 A flowing when I short, maybe if I use a germanium diode instead of a silicon?
  11. audioguru, you can tell me what the special features mc34071 have? I noticed that when the current control operates (at minimum), still have 0.7 volts in the input of oamp (due to the diode), multiplying by the gain, we have ~ 1.8 V, so in case of short-circuit 0.6A pass because of the output resistor of the 2n3055. is there any way to reduce it?
×
  • Create New...