Electronics-Lab.com Community

# terrakota

Members

13

Never

1. ## newbie pot usage

good, i think will have to wait to advance more in my study thanks a lot for your great help
2. ## newbie pot usage

ok, got the idea so the pot's are only usefull to use with small currents like audio signals, etc? I have in my home a lamp connected to the 120v ac, that you can control the light brigthnes with a pot, maybe is a high rated power pot? thanks for your help
3. ## newbie pot usage

hi, I'm a completle newbie in electronics what I'm trying to do is to control the brightness of a 6v lamp with a 6 volt battery whit a 50k potentiometer, will i damage the pot because the power dissipated in the pot? how can i solve the circuit if there's a risk to damage the potentiometer? i think that when the pot is at near zero resistance the current will be high and power too throw the pot, thanks for any help and please excuse my poor english
4. ## peak voltage

hi, I'm a little confused when and when not take in account the peak voltage, i understand that when i use pure DC i dont need to worry about the peak voltage value but if I'm working with AC voltage like in power supply applications i must take peak value in account, my question is at what point peak voltage dissapear? or no longer exists? ie, in a power supply application that converts AC to DC and "reduce" the AC voltage u use a bridge rectifier and some capacitors, to choose the rigth capacitor filtering i need to take in account the AC voltage(ripple?) but after capacitor filtering an AC voltage not exist any more so, theres no more a peak voltage? with pure dc voltages like batteries?. am i right? how i deal with peak voltage or when the peak voltage dont exists any more. please excuse my poor english
5. ## newbie confused with voltage dividers

know i have a more clear concept, thanks to all for your great help
6. ## newbie confused with voltage dividers

thanks ok but suposse i connect another device to the remaining voltage, this will affect too the total circuit current? supose is a dc motor i tnihk the dc motors have resistance too, so my quistion must i consider the devices resistance too? thanks for any help
7. ## newbie confused with voltage dividers

Hi, I'm learning electronics from a book and know im on the voltage dividers topic, i fully understand how it works and how perform calculations about it, but i'm confused using vd in real life, heres an example: a have a 9v source and need to connect 2 devices, one needs 3 volts, and the other 5 volts, ok i can connect 2 resistors in series previous calculations and everything looks fine, if the total circuit current is ie. 500mA that means that 500mA and 3 volts exists in R1 and 500mA and 5 volts in the second resistor, ok if i connect a load(ie. a led) into R1 the current througth R1 will be the same? or i have a new circuit with R1 in parallel with the load?, if that is the case i must consider the device(load) resistance? how i know that device resistance? can i use a multimeter to measure every device resistance then design the circuit? with the new resistance found from the load, all devices have some kind of resistance? how can i attack that problem? is there a formula or something to do this? is there a goodtutorial, guide, etc? thanks in advance and please excuse my poor english by the way the book only says how can i divide voltage if i need diferent values for diferent devices but dont take in account the current behivor with the load connected.