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# deathbyampere

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1. ## series/parallel circuits and dividers

My apologies for a second post concerning dividers, but I didn't want to detract from the information being given to that other fellow. Also, please pardon my rather morbid profile; it seems to be true, but I will change it if anyone finds it offensive. Now, to the heart of the matter. I'm taking an electronics course and now I am at a loss. At present, the course requires that I read a simple schematic, calculate for the missing or needed value(s), build that circuit, and finally measure it. My calculations never match the measurements (if the circuit works at all). I couldn't find a good schematic for this, so pardon the use of random symbols: _____________________________ | | | | R1 | | | ____________ | bat | | | | R2 R5 R6 | | | | | |_______ | | gnd | | | | | | | | R3 R4 | | | | | | | | | | gnd gnd gnd gnd Where R1 = 30 ohms R2 = 25 ohms R3 = 10 ohms R4 = 40 ohms R5 = 20 ohms R6 = 10 ohms V(bat) = 9V To figure the total resistance, am I correct in doing the following: R3 x R4 / R3 + R4 = Re1... Re1 + R2 = Re2... Re2 x R5 / Re2 + R5 = Re3... Re3 + R1 = Re4 Re4 x R6 / Re4 + R6 = Rt or Re1 = 8 Re2 = 33 Re3 = 14.2 Re4 = 44.2 Rt = 8.1 ____________ Now, if that is right, the current should be appx. 1.125A, yes? ____________ Here's where I get more lost. As I try to figure the voltage drops, would I figure R1 and R6 separately (resulting in an untenable answer) or figuring that drop for R1-R6 as a parallel branch? If so, how do I find the voltage drops for R1 and R6 respectively, and on down the line? My apologies for this pedantic, long-winded, and ridiculous question. If anyone has articles that would be helpful, I'd love to see them. As it is, I'm probably going to pull my hair out and certainly going to electrocute myself at this rate. Sincerely.
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