Jump to content
Electronics-Lab.com Community


  • Posts

  • Joined

  • Last visited

Recent Profile Visitors

The recent visitors block is disabled and is not being shown to other users.

Kerrowman's Achievements

  1. Thanks. A useful idea but wouldn’t need to house in a case. More a question of how to place all the parts on and around my circuit.
  2. I have built a device that has a spinning rotor that I would like to display its rpm. I have been using a handheld laser device that bounces off a reflective strip on the rotor (see pic). I’m looking for a permanent module attached to the base plate with a small display unit I can mount and with any electronics put on the PCB I’m preparing. Magnetic options are complicated as the rotor has 5 Neo magnets in it so an optical method is preferred. Any ideas? Thanks
  3. I know nothing about your post or why it was removed.
  4. Hi Harry, That makes sense but in the case of the ignition coil HV systems, like in the link you gave, they can operate at a similar frequency of say 200-500Hz and still give very powerful sparks so is the construction of an ignition coil, and also a flyback transformer, different to such a degree that they avoid this pulse width issue? I'm inspired to build one or other of the attached, although the 555 based one has some useful duty and frequency adjustment. Maybe one of these will deliver 10+kV to my cell without significant losses? Julian
  5. Thanks Harry, I will certainly look into using ignition coils or perhaps a Tesla coil. If it's a question of impedance matching then surely I only have the option to up the secondary coil's impedance. Given that at the moment its resistance is about 1 Ohm, then does it make sense to add a 1 MOhm resistor in series with it to bring it more in line with the 1.6 MOhm resistance of the water cell? Or will that not work or introduce other problems? Julian
  6. It's interesting that you, in effect, got + and - 3.7kV across the output of the coil. That is certainly the sort of level I would expect, in which case I would expect more than the 3V I get when I attach my secondary to my load (water cell). Which brings me full circle to my earlier question, why am I getting only 3V across my water cell terminals when your simulation and your ignition coil experiments show much more? Perhaps I should build a Tesla coil and zap my water cell with that? As a square wave can be thought of a complex mix of different frequencies of sine waves (Fourier analysis) I think using a square wave in a transformer will result in higher losses at the higher frequency end so producing a rounded square wave output with some enhanced ripple. When that encounters the water cell that will undoubtedly modify the waveform but I haven't observed that yet.
  7. Harry , I need to unpick what you have found. The highest output across the secondary of your coil was 159.8V, when I presume one would expect several kV? (I don't know what the turns ratio is in such a coil but ignition systems are designed to produce 5-15kV) Am I correct in saying that to get a higher secondary output one will need a bigger primary current - to store more energy in the primary coil? Also are you saying that the current in the primary is a function of the Gate frequency - perhaps a lower frequency will allow more current into the primary? What's DUT? Regards, Julian
  8. Harry, that's very industrious of you to build a physical version of the circuit. Have you have substituted my upper 530 for a light bulb because it is just acting as a variable resistor? Also could you clarify if you got a high voltage on the secondary of the ignition coil? If you did, even with the small currents you measured in the primary, what does this all mean for my current design 'HV Supply 1B' shown a few posts back? Julian
  9. Hi Harry, I'm not clear where your two variable resistors are and in the attached Pic 1 I have put where I think one is. My supply is set at 50V and the gate pulses at 200Hz, 50% so 'hoping' to be able to get 750-1kV out at the secondary when connected to the electrolysis cell. As I come from a Physics background and not electronics I'm trying to understand why increasing the current in the primary will increase the voltage across the cell. Is the problem that the 530 is throttling both the voltage and the current and hence the multiplication by the secondary? From my limited experience of Spice I think one can have a pot in the design together with a simple statement that increments the value of a resistor R. I attach a grab of an early attempt (Pic 2) at a regulator using this approach that someone else advised me on together with the relevant files (not sure which is essential so I've provided three). Perhaps you can incorporate some bits of it into your simulation? I appreciate your efforts, thank you, Regards, Julian V Adjust Circuit.asc V Adjust Circuit.log V Adjust Circuit.net
  10. Hi Harry, In your first reply at the start of this thread you suggested using a second MOSFET to control the current instead of a variable resistor, which is why I modified the circuit to include the IRF530. While it works to allow fine control of the current are you now suggesting I put a 50 Ohm resistor instead, based on your simulation? If so then this would surely need to be a 200W resistor (massive?) to be able to cope with 2A through it and I certainly don't have one of those - which is why I presume you suggested the FET in the first place. J
  11. Hi Harry, I inserted a 1.5 Ohm resistor into the Source line of the IRF840 as suggested (Pic 1) and calculated typical readings of the primary current of 30mA when the secondary was unloaded and about 160mA when the cell was connected (Pic 2), The value under load could have gone higher but not as high as 1A. This was with a square wave input of 200Hz from the pulse circuit and 12V from the PSU as before but with my bifilar coils in place (Pic 3). Once again the voltage across the cell drops to 3-4V under load and reads about 220V when the cell is not connected. I know to expect a voltage drop when more current is flowing but I can’t explain why it drops so much when the load is attached. Since my aim is to put 1000+V across the electrodes of the cell (with distilled water) how can I achieve this if the moment the load is connected the voltage drops to almost nothing? I don't think it's a weakness in my variable power supply that feeds the transformer and it's the same with or without the bifilar coils that are designed to limit the current in the cell. Julian
  12. Thanks. I will see what current is flowing in the primary and report back.
  13. Hi Harry, The cell measure 1.164 M Ohms and a capacitance measurement using the same meter showed 1.058mF. That last reading is surprising since I did a calculation last year based on plate area, separation and the dielectric of water which came to 5.18nF so either the meter reading is unreliable in that context or the distilled water surrounding the cell is contributing in some way. With the resistance measurement that would suggest that the average current flow through the cell was 50/1.164 E6 = 42uA where 50 is a typical rounded voltage peak I'm getting on the scope. I'm unclear how such a small current (about 30mA from the variable PSU) would result in such a big voltage drop. Is the way to keep the voltage across the cell up a beefier transformer and variable PSU? Thanks for your time. Julian
  14. Hi Harry, I tried using a 0.22uF, 2kV capacitor across the secondary windings and Pic 1 shows the result without it and Pic 2 with the capacitor. Pic 3 is with no capacitor but instead with a diode across the secondary windings, as shown in the circuit in Pic 5 (but without the bifilar coil that I have yet to add in). Pic 4 is with the load attached, the load being a simple cylindrical electrolysis cell in distilled water. It seems that with the load attached, and only about 50mA being drawn from the Variable PSU, the voltage across the secondary windings and cell drops dramatically to around 3 V which is disappointing. I'm hoping the when the bifilar coil is added that I will get some decent voltage spikes to compensate. Is this voltage drop caused purely by whatever current is flowing through the electrolysis cell and is there a simple way to boost it back up? Julian
  15. Harry, I will set it up with the load in the next day or so and also add a 1uF, 2kV capacitor across the secondary coil and report back. I'd be interested to see what the simulations shows. Thanks Julian
  • Create New...