cantbeatpar Posted May 3, 2004 Report Share Posted May 3, 2004 I have a very basic knowledge of electronics so this will probably seem pretty stupid to you guys but here goes. I have 6V DC Supply at 500 milliamps. I need to know what size value capacitor to use to get a 5 to 7 second delay before energizing the load.Thanks Mike Quote Link to comment Share on other sites More sharing options...
audioguru Posted May 3, 2004 Report Share Posted May 3, 2004 Hi Mike,Welcome to this community.So far, you have gathered most of the information that you need:1) You have a power supply with a full description and its ratings.2) You described a purpose: a certain time delay before energizing the load.3) You know that a capacitor takes time to charge.But the capacitor needs to be part of a timer circuit, which activates a transistor switch. Please look in our projects section for a timer and I'll look too. Quote Link to comment Share on other sites More sharing options...
hotwaterwizard Posted May 4, 2004 Report Share Posted May 4, 2004 Try my timer it works well on 6vdc too!Use a smaller capacitor like 1 uf to 47uf and experiment with it. It is a delayed off timer. When you push the switch it turns on the load and turns it off after the timming cycle. off. If the switch is pushed again durring the timing cycle it resets the time limit. Quote Link to comment Share on other sites More sharing options...
hotwaterwizard Posted May 4, 2004 Report Share Posted May 4, 2004 Here is a Delayed on Relay Quote Link to comment Share on other sites More sharing options...
audioguru Posted May 4, 2004 Report Share Posted May 4, 2004 Hotwaterwizard,Your "delayed on relay" is a good circuit that will do the job, but with only a 6V supply, the input divider should be changed.If you use 220K for both divider resistors, and a 100 microfarad capacitor, I figure that the delay will be about 6 seconds.Use another 2N3904 transistor to replace the obsolete MPSU10, and use a small relay.The power must be turned-off for at least 30 seconds, or else the next delay time will be shortened.Mike,Do you understand how to build this circuit? Quote Link to comment Share on other sites More sharing options...
Kevin Weddle Posted May 6, 2004 Report Share Posted May 6, 2004 Has anybody seen the sawtooth wave generator that uses a PUT in parallel with a capacitor to get rapid discharge. The input overdrives the PUT past a short, but allows voltage across the capacitor. When the input drops, the capacitor will rapidly discharge. Quote Link to comment Share on other sites More sharing options...
Guest Yevgenip Posted May 24, 2004 Report Share Posted May 24, 2004 Is there a Formula for Calculating the delay in a timer circuit? Quote Link to comment Share on other sites More sharing options...
audioguru Posted May 24, 2004 Report Share Posted May 24, 2004 Yevgenip,The formula for charging a capacitor through a resistor from a fixed voltage source is:R X C. Where R is in Ohms and C is in Farads. The result of the multiplication is in seconds, when the capacitor will have reached a voltage that is about 0. 63 of the fixed voltage. To calculate the time for it to charge to another voltage level, I refer to a graph in a book.For example, A 1M resistor charges a 10 microfarad capacitor in 10 seconds.The capacitor will almost reach its full charge (almost to the fixed voltage level) in a time that is 5 times as long.These calculations depend on having a measuring device or sensing circuit that has an input resistance that is much higher than the resistor doing the charging. Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.