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how to calculate??


only_lonely

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This isn't at all biased right. What transistor are you using? There isn't any current because you don't have a potential difference between the base and emitter. Keep the emitter positive and use a resistor to ground on the base. I don't see a signal input so I'll assume that this circuit is about constant current adding or subtracting. R1 is just for bias and C3 creates the impedance as seen by the signal through the diode.

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Hi Ray Orbison wannabe or fan,
If you want the rise-time of the voltage across C3 to be the same, then you simply multiply the value of R1 by the ratio of supply voltages, which is 12 divided by 4.5, so it will be about 12.5K to 12.7K.
If the circuit is activated by the junction of R3 and R5 going close to ground, and you want the same low LED current, then multiply the value of R5 by the different voltage ratio that will be across it (subtracting the voltage across the LED).

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