walid Posted October 27, 2005 Report Share Posted October 27, 2005 I write the following prog to simulate the circuit shown in Fig.C-E below:common E Amp freq responseVCC 7 0 DC 12VS 1 0 AC 1Q1 4 3 5 Q_2N2222A_NRS 1 2 1KC1 2 3 2uFR1 3 0 10KR2 7 3 30KRC 7 4 4.3KRE 5 0 1.3KC3 5 0 10uFC2 4 6 0.1uFR3 6 0 100K.MODEL Q_2N2222A_N NPN( IS=11.9F NF=1 NR=1 RE=649M RC=1 + RB=10 VAF=83.5 VAR=41.7 ISE=350F ISC=350F + NE=1.58 NC=1.58 BF=204 BR=5 IKF=149M + IKR=149M CJC=13.1P CJE=30P VJC=2.87 VJE=678M + MJC=330M MJE=330M TF=531P TR=69N EG=1.11 + KF=0 AF=1 ).op.endThe .op command results are:NAME Q1 MODEL Q_2N2222A_N IB 1.25E-05 IC 1.71E-03 VBE 6.66E-01 VBC -1.74E+00 VCE 2.40E+00 BETADC 1.37E+02 GM 6.53E-02 RPI 2.35E+03 RX 1.00E+01 RO 4.90E+04 CBE 8.44E-11 CBC 1.12E-11 CJS 0.00E+00 BETAAC 1.54E+02 CBX 0.00E+00 FT 1.09E+08 And I need to discuss some of these results with you:(1) How far or close these results to the real life, can i depend on it initially?(2) RPI is the i/p impedance looking into the base of Q1, so, the total i/p impedance is: R1//R2//RPI = 1.8K ohm. so we can look at the i/p portion of the circuit as: Vs connected in series with Rs then to C1 then connected inseries to that 1.8k. if we look at Vs as a MIC and Rs as the impedance of the MIC and C1&Rtot as a high pass filter, is the value of C1 suitable and why?(3) What exactly these parameters mean: GM, RX, RO, CJS, CBX.(4) FT is (as I remember) is the freq at which the gain =1, that is at this freq there is no amplification, Is this OK?(5) In the MODEL Q_2N2222A_N, BF = 204 is this the upper value that this Q can reach?(6) In the MODEL Q_2N2222A_N, what these mean: NF=1 NR=1 NE=1.58 NC=1.58 IKF=149M IKR=149M VJC=2.87 VJE=678M MJC=330M MJE=330M TF=531P TR=69N EG=1.11 KF=0 AF=1 thats allthank you in advancewalid Quote Link to comment Share on other sites More sharing options...
prateeksikka Posted October 29, 2005 Report Share Posted October 29, 2005 i thought that spice (atleast the one that comes with orcad) is a pick and place software.Do you really write code for it? Quote Link to comment Share on other sites More sharing options...
walid Posted October 29, 2005 Author Report Share Posted October 29, 2005 What do you want? Quote Link to comment Share on other sites More sharing options...
audioguru Posted October 29, 2005 Report Share Posted October 29, 2005 Hi Walid,Do you think that Spice will show the terrible distortion of your transistor stage? Quote Link to comment Share on other sites More sharing options...
walid Posted October 29, 2005 Author Report Share Posted October 29, 2005 Hi all 1) I don't understand what prateek mean!2) thank you Audioguru for your interest though I don't know what the lettet you whant to receive me?3) all those replys are out of my question.yours, walid Quote Link to comment Share on other sites More sharing options...
prateeksikka Posted October 30, 2005 Report Share Posted October 30, 2005 hi walid !i guess the output results give the transconductance and resistance both input and output for the configuration.I meant by asking the question that i use a pspice software which gives me simulation results just by one click.why do u write a long code for it? Quote Link to comment Share on other sites More sharing options...
audioguru Posted November 25, 2005 Report Share Posted November 25, 2005 Hi Guys,I've been playing with a Spice simulator program.I took an ordinary single transistor amplifier stage then fed it a signal level that is lower than would cause the transistor to saturate or be cutoff.With the emitter resistor bypassed, it had high gain but also had 40% distortion. The top part of the wave was severely compressed and you can't even read its gain.Without the emitter bypass capacitor its gain was reduced but the negative feedback also reduced its distortion to 3%. Quote Link to comment Share on other sites More sharing options...
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