sundin13 Posted February 21, 2006 Report Posted February 21, 2006 Well it didn't take me long to get stumped again. The only formulas I have for ICQ & VCEQ need a VBB. With this circuit there is no VBB, am I right? Any help would be great. We're not using any curve charts or data sheets, just formulas, which are not in my text book. Q is queiscent. ???Determine:a.) ICQ (in mA) (Without using Vb= VccxR2/(R1+R2)) <---voltage dividerb.) VCEQ (in Volts)Regards.... :D Quote
audioguru Posted February 21, 2006 Report Posted February 21, 2006 1) R1 and R2 make a voltage divider. You don't need the formula to determine their divided vol tage, just use Ohm's Law.2) Subtract the Vbe voltage to determine the emitter voltage and its current.3) Use Ohm's Law to determine the collector voltage from the emitter current.4) If you want to get extremely accurate, correct the calculations using the value of beta that is given. Quote
sundin13 Posted February 22, 2006 Author Report Posted February 22, 2006 I've got it figure out. The Q was throwing me off. As far as I know the Q-point is on the dc load line if I'm not mistaken. This stuff doesn't get any easier thats for sure. Quote
audioguru Posted February 24, 2006 Report Posted February 24, 2006 By 'quiescent', do you mean DC?Is it always Synonymous to DC?Its quiescent-point is when it rests without signal. Its DC conditions. Quote
bhargava Posted February 26, 2006 Report Posted February 26, 2006 Hi Sundin,I've worked the problem out for verification these are the answersIcQ =1.64mAVCEQ= 6.68VThe equtions used the logic ,theory almost every thing is lucidly explained in Electronic Devices and circuits by MILLMAN & HALKIAS from TMHok then Bye...Bhargava Quote
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