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# Tank ckt

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Hi to all

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A tank is an inductor and a capacitor in parallel and they resonate.
At the resonant frequency their impedance is very high and current transfers back and forth between the inductor and the capacitor.

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You neglected to explain about their impedance values at resonance... and what about "Q"??

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Hi Indulis,
I think Shahzad is a nooby. I answered him with the basics but if he asks for more details then you be his teacher.

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HI

does tank ckt works like this shown in figure

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No... that waveform looks like a simple RC integrator.

At resonance it would oscillate at 1/2*pi*(L*C)^.5

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Hi indulis
my main question is that how it produces sharp wave form

Thanks

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Anything that resonates with a high impedance makes a sine-wave. A sine-wave is very smooth without sharp edges. Sharp edges on a wave are caused by harmonic distortion because harmonics are added. A sine-wave doesn't have harmonics, just the fundamental frequency.

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Hi audioguru

Anything that resonates with a high impedance makes a sine-wave

can u please explain this point by mathematical way
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Hi audioguru

can u please explain this point by mathematical way
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At resonsance, the impedance approches infinity (this of course is impossible... there are always circuit paracitics).

From the WWW...

The solution to the circuit (which is a second order differential equation) is

i(t) = Ae ^+ jωt + Be ^− jωt

Considering the initial conditions, solve for A and B.

Because there is a complex exponential (thats the "j" part), the solution represents a sinusoidal alternating current.

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• 2 weeks later...

When calculating a tank, does the high impdeance differ if Xc=Xl=50 ohms from Xc=Xl=100 ohms?

When you connect the tank at the collector of a transistor, at DC the collector is at the supply voltage. When you apply the signal, does the peak hit the supply voltage, then go down from there with the size of the ouput signal? In other words, at what DC does the signal hover?

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When calculating a tank, does the high impdeance differ if Xc=Xl=50 ohms from Xc=Xl=100 ohms?

Hi Kevin,
Welcome back. ;D
The impedance of a tank circuit at resonance is determined by its Q. Usually it is the inductor's resistance that reduces the tank's Q. Therefore an inductor with a lower reactance would have a lower resistance then the tank would have a higher Q and a higher impedance, but with it the bandwidth is reduced.

When you connect the tank at the collector of a transistor, at DC the collector is at the supply voltage. When you apply the signal, does the peak hit the supply voltage, then go down from there with the size of the ouput signal? In other words, at what DC does the signal hover?

I haven't looked for many years, but when the DC collector voltage averages at the supply voltage because the resistance of the inductor is very low, then I think the signal voltage at the collector varies above and below the supply voltage.
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Thanks for leading me in the right direction concerning the first question. I had hoped a larger reactance might mean a higher impedance. Kind of disappointing. I don't like the second answer either. I was hoping it would just pull away from the supply voltage. Oh well.

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