sundin13 Posted September 9, 2006 Report Share Posted September 9, 2006 Hey I'm a ;Dtech student in need of some help.A 34V dc supply is applied to an SCR in series with a resistor, R. When the SCR is turned on, its Ih= 6mA, and V a-k= 0.7 V. What is the minimum value of R before the SCR can turn off?Rmin=_______ohms rounded to the nearest hole number.Do I just divided 34V by 0.006 Amps or would that be the Max value...Confused??? Any help would be great... Quote Link to comment Share on other sites More sharing options...
audioguru Posted September 10, 2006 Report Share Posted September 10, 2006 Hi Sundin,Think about how much voltage will be across the resistor. It is less than 34V. That voltage divided by the spec'd holding current determines the minimum value of the resistor. What about the tolerance of the resistor? Quote Link to comment Share on other sites More sharing options...
sundin13 Posted September 10, 2006 Author Report Share Posted September 10, 2006 Oh yeah series circuit basics. Ooops...So the other voltage drop would be 33.3 Vdc. Now the smallest the Resistor value before turn off would be 33.3 divided by .0065550 Ohms......Am I right?Resistor tolerences are not factored in. Thanks Audioguru Quote Link to comment Share on other sites More sharing options...
audioguru Posted September 10, 2006 Report Share Posted September 10, 2006 Hi Sundin,You are correct! ;D Quote Link to comment Share on other sites More sharing options...
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