bitem2k Posted January 24, 2007 Report Share Posted January 24, 2007 Im currently reading a book on electronics, that says that the sum of the Voltage drops across all components tied in series should equal the voltage of the battery.However i tested cicuit on a breadboard with a led and a resistor, and measured the drops accross each and added them together. They did not add up to the supply voltage.Anyone have any ideas?Thanks very much. :) Quote Link to comment Share on other sites More sharing options...
audioguru Posted January 24, 2007 Report Share Posted January 24, 2007 Please tell us what are your voltage measurements.Measure the battery voltage with it powering the LED when its voltage is reduced by the current. Quote Link to comment Share on other sites More sharing options...
bitem2k Posted January 24, 2007 Author Report Share Posted January 24, 2007 Thanks for the reply.worked out what the problem was.This is very strange, but i was using a Nokia Charger which provides 8.78V with nothing connected., but for some reason when you measure the drops across everything connected (resistors) in series, it looses a volt or two!Any idea why?thanks Quote Link to comment Share on other sites More sharing options...
audioguru Posted January 25, 2007 Report Share Posted January 25, 2007 The voltage dropped on the Nokia charger because it is a constant current source or because it was overloaded or because it has lousy voltage regulation. Quote Link to comment Share on other sites More sharing options...
bitem2k Posted January 25, 2007 Author Report Share Posted January 25, 2007 Righto.Thanks Quote Link to comment Share on other sites More sharing options...
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