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hi
Today, I sat thinking at this point, what happens when the i/p impedance for the subsequent stage is less than the o/p impedance of the past stage? Please clarify the idea
Thank you

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The impedances form a voltage divider and reduce the level of the signal.

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thank you guru

from what you said, if the o/p impedance of the first stage = 9K
and the i/p impedance of the next stage = 1k
and the signal is 1V
only (1/10) of that signal reach to the next stage
that is 0.1 volt.

If so, the word dowenload be inappropriate because I understand that the characteristics of the first stage change!

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Hi Walid,
Yes, the 1V signal is attenuated to only 0.1V.

When you put too much load on a donkey (or a camel) then it goes slower or it stops because it is loaded down.

Overloaded would be a better word but it sounds bad. An attenuator is not always bad, sometimes it is wanted.

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A very good example
thank you guru

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