walid Posted April 10, 2007 Report Share Posted April 10, 2007 hiToday, I sat thinking at this point, what happens when the i/p impedance for the subsequent stage is less than the o/p impedance of the past stage? Please clarify the idea Thank you Quote Link to comment Share on other sites More sharing options...
audioguru Posted April 10, 2007 Report Share Posted April 10, 2007 The impedances form a voltage divider and reduce the level of the signal. Quote Link to comment Share on other sites More sharing options...
walid Posted April 10, 2007 Author Report Share Posted April 10, 2007 thank you guru from what you said, if the o/p impedance of the first stage = 9Kand the i/p impedance of the next stage = 1kand the signal is 1Vonly (1/10) of that signal reach to the next stagethat is 0.1 volt.If so, the word dowenload be inappropriate because I understand that the characteristics of the first stage change! Quote Link to comment Share on other sites More sharing options...
audioguru Posted April 10, 2007 Report Share Posted April 10, 2007 Hi Walid,Yes, the 1V signal is attenuated to only 0.1V.I don't say downloaded. I say the signal is loaded down.When you put too much load on a donkey (or a camel) then it goes slower or it stops because it is loaded down.Overloaded would be a better word but it sounds bad. An attenuator is not always bad, sometimes it is wanted. Quote Link to comment Share on other sites More sharing options...
walid Posted April 11, 2007 Author Report Share Posted April 11, 2007 A very good example thank you guru Quote Link to comment Share on other sites More sharing options...
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