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Adding a Digital Multimeter LCD to XP-720


d4rkzone

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Hi,

I want to add to my power supply which is 0 - 20 V+/- @ 1 A and +5V @ 3A a LCD DMM.  I want to use a 9V battery due the load of the LCD will be independent of the circuit.

So I made a search. I want to make the following circuit: xp720adddpmschem.th.gif

It is capable of switch between each output and to measure the output current. The problem is that I am having difficulties understanding the circuit shown.

I don't understand what is the I-Sense resistor, and the "To +Vout Via Main board" outputs. Do I need to connect this directly to the cable that goes out from the PCB right?

In addition he was talking about: "There are no RF decoupling capacitors in the circuit". Then he added some capacitors, for what this is benefit?

Source: http://www.io.com/~n5fc/xp720.htm

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It's difficult to show you without a copy of the original power supply.

The 'To +' and 'To -' inputs jusst go to the positive and negative supply outputs respectively.

The current sense resistors go in series with the outputs but still enclosed in the feedback loop.

I have a feeling that the current sensing has been incorrectly implemented. If this is a simple LM317 circuit connecting a resistor between the output and potential divider ruins the regulation. It's difficult to know because it's a 0-20V power supply, not a 1.25V to 20V supply, so there's probably more so it than a simple LM317 supply.

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