karthikeid Posted June 7, 2010 Report Share Posted June 7, 2010 hii have posted a circuit wch is a voltade divider in this wat must be the wattage of the resistor?? the load is the 4leds in parallel.tell me the calculation too. Quote Link to comment Share on other sites More sharing options...
Hero999 Posted June 7, 2010 Report Share Posted June 7, 2010 R2 isn't needed because LEDs need a constant current not a constant voltage.Use the normal LED resistor formula which can be found using Google and calculate the power dissipation in the resistor using Ohm's law P = I2R Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.