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TIP142 Stepper motor driver

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IB = base current.
V = logic voltage, which you haven't given so I assumed 5V.
VBE = base emitter voltage which is on the datasheet and is typically 1.4V for a Darlington pair.

The TIP142's saturation voltage (VCEis specified with IB = IC/100.

With an IC of  1.7A and an IB of 17mA, VCE is typically 0.75V

If the base current is lower, then VCE will be higher, if IC is still 1.7A but IB is reduced to IC/4000 = 425

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