rfranzk Posted October 19, 2010 Report Share Posted October 19, 2010 Hello all, I want to build a two or three light display that is driven by the fence charger and can be seen from 1/4 to 1/2 mile away. I was thinking of using a voltage divider network and either xenon or neon tubes with reflectors and lenses. The bulbs I am considering are neon standard brightness (http://www.chml.com/products/pdf/5-4.pdf) that draw .3 ma current and breakdown at 115vdc. I would like to have an indicator of 2kv, (red lens) 4kv (Yellow lens) and 6kv (green lens) highest kv flashing all 3 lamps. The questions I have are related to current draw and load on the fence and also since the input voltage is what varies, how to calculate the divider circuit. The input could be has high as 10 kv but more likely in the 7.5 to 8 kv range. I assume the divider should supply approximately 115 volts at each resistor to light the lamp. If I calculate for an 8 kv input will the voltage increase be too much at the display with a 10 kv input causing bulb failure? Will a partially shorted fence, ie weeds touching fence cause the voltage to drop below levels of flashing the 2kv lamp? The voltage is not applied constantly but in 50 ms pulses at intervals of 500 ms to 1000 ms. I know the bulb current draw can load the fence and cause reduced effectiveness. If two lights are better for efficient fencer output I can live with that. Or circuit that would only flash one light depending on input. Any recommendations would be greatly appreciated. Thanks in advance. rfranzk. Quote Link to comment Share on other sites More sharing options...
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