Guest Sherial Posted November 4, 2012 Report Share Posted November 4, 2012 Hello,I have a question that is on a study guide for a final exam.In a high-pass filter, Xc = 500 Ω and R=2.2kΩ. What is the output voltage (Vout) when the input voltage (Vin)=10 V.The given answer is 9.75 /_ 12.8 degrees. I cannot get this answer from my calculations below.I have calculated it two different ways and come up with two different answers that don't match the given one.Z= √(500^2+2200^2)=2256.1Ω10V/2256.1Ω= 4.4 mAVr =.0044*2200=9.68 VVXc=.0044*500= 2.2 VTan^-1 (2.2/9.68)=12.80When I plug the numbers into my TI-89 to get the polar coordinates I get 9.92/_12.8 degreesSecond try10V/2700Ω= 3.7 mAVr=.0037*2200=8.14 VVXc=.0037*500= 1.85 VTan^-1 (1.85/8.14)=12.80When I plug the numbers into my TI-89 to get the polar coordinates I get 8.34/_12.8 degreesI have been pulling my hair out for the last couple days trying to figure this one out.Thanks for the help Quote Link to comment Share on other sites More sharing options...
Lyker Posted November 4, 2012 Report Share Posted November 4, 2012 You are just chopping off to many digits on the current.Your current is 4.432mA not just 4.4mASo....4.432mA * R(2k2) = 9.75V4.4mA * R(2k2) = 9.68V Quote Link to comment Share on other sites More sharing options...
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