electronicslab_satya Posted February 5, 2014 Report Share Posted February 5, 2014 Hi,I have this very simple clarification. I have a circuit with a voltage source and two resistors R1 and R2 in series. I use the KVL equation to find the current. I use the passive sign convention and explained my problem in the attachement. Please clarify my doubt.Thanks and regards,satyaclarify.pdf Quote Link to comment Share on other sites More sharing options...
Guest rajeshr Posted February 6, 2014 Report Share Posted February 6, 2014 the equation should be V2=IR1+Vso V=V2-IR1=5-0.025X100=2.5V Quote Link to comment Share on other sites More sharing options...
redwire Posted February 6, 2014 Report Share Posted February 6, 2014 In your diagram you assumed the current flowed clockwise and then showed + and - convention over the resistors indicating a voltage drop across them. Your equation becomes 5v -I*R1 - I*R2 =0; With R1=R2 ; I = 0.025A. Going back to the original diagram working from the voltage source to point A you have 5V- I*R1 = 2.5V. Note that if you had incorrectly assumed the current flow and it was really counter clockwise then I would be negative meaning you assumed the wrong direction but the answer would work out. Quote Link to comment Share on other sites More sharing options...
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