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Calculation of voltage using Kirchoffs laws


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In your diagram you assumed the current flowed clockwise and then showed + and - convention over the resistors indicating a voltage drop across them.  Your equation becomes 5v -I*R1 - I*R2 =0;  With   R1=R2 ; I = 0.025A.  

Going back to the original diagram working from the voltage source to point A you have    5V- I*R1 = 2.5V.   Note that if you had incorrectly assumed the current flow and it was really counter clockwise then I would be negative meaning you assumed the wrong direction but the answer would work out.    

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