Guest mourad3d Posted November 14, 2014 Report Share Posted November 14, 2014 I have a problem form Amplifier voltage divideIs a problem that the ability to show me that the program Multisim itself is not showing me in the following accountsWhere the capacity of the planned 1.2 ml Watt, but the 8 Micro program show what the cause of itKnowing that the impedance of the biggest income impedance phase out AlsabakyAttachment filesvoltage_divide_-_1.pdf Quote Link to comment Share on other sites More sharing options...
Guest liquibyte Posted November 14, 2014 Report Share Posted November 14, 2014 What? Can you slow down and try that again, maybe in your native language and we'll translate? Quote Link to comment Share on other sites More sharing options...
Guest mourad3d Posted November 14, 2014 Report Share Posted November 14, 2014 thank you This amplifier circuit in the form of voltage divide I make some calculations to extract the circuit's capacity was 1.2 ml WattWhen the work program of simulation result of the ability did not show the exact reason for this Quote Link to comment Share on other sites More sharing options...
Guest mourad3d Posted November 15, 2014 Report Share Posted November 15, 2014 Ok the schematic Can you Download of the linkhttp://www.m3dmax.com/3d/Tran.zipI'm doing you the ability accounts, but the ability to Multisim program different Wayne error resultsvoltage_divide_-_1.pdf Quote Link to comment Share on other sites More sharing options...
Guest liquibyte Posted November 16, 2014 Report Share Posted November 16, 2014 Someone else might be able to help you but I can't run Multisim, my OS is Linux and it won't run in WINE. Quote Link to comment Share on other sites More sharing options...
Guest mourad3d Posted November 16, 2014 Report Share Posted November 16, 2014 the schematic Quote Link to comment Share on other sites More sharing options...
audioguru Posted November 16, 2014 Report Share Posted November 16, 2014 I do not know why so many calculations were made for the very simple circuit, most of the calculations are not needed to simply find the RMS power in the 5K ohms load.I simulated the circuit with LTspiceIV and it shows an output power of 9.0uW in the 5k ohms load. Quote Link to comment Share on other sites More sharing options...
Guest liquibyte Posted November 16, 2014 Report Share Posted November 16, 2014 Interesting waveforms. That's one of the things I love most about this program. Here's an LTSpice IV file I did.Draft1.asc.zip Quote Link to comment Share on other sites More sharing options...
Guest mourad3d Posted November 16, 2014 Report Share Posted November 16, 2014 Are you can How calculations output power In this circle of if load 5k ohms To be equal to simulation Quote Link to comment Share on other sites More sharing options...
Guest liquibyte Posted November 16, 2014 Report Share Posted November 16, 2014 I get 410 microwatts or 41 milliwatts unless I'm doing the math wrong.Right click the name of the waveform at the top and attach cursor one to the first waveform and cursor two to the second and hover over each and move them to the peaks. The window that pops up will show you the resultant value for the waveforms and then you do the math on those two values. Quote Link to comment Share on other sites More sharing options...
Hero999 Posted November 16, 2014 Report Share Posted November 16, 2014 You need to wait until the steady state, before attempting to calculate the power in the load. When the power is first applied, there will be a power surge as the DC bias voltage stabilises; it takes awhile for the capacitors in the circuit to charge.Once the steady state has been reached, the RMS power in the load can easily be calculated: PRMS = Vpk-pk2/8RL Quote Link to comment Share on other sites More sharing options...
audioguru Posted November 16, 2014 Report Share Posted November 16, 2014 Liquibyte,You have the transistor shorted with a wire from its collector to its emitter instead of a 10M voltmeter. Quote Link to comment Share on other sites More sharing options...
Guest liquibyte Posted November 16, 2014 Report Share Posted November 16, 2014 Liquibyte,You have the transistor shorted with a wire from its collector to its emitter instead of a 10M voltmeter.I knew there must be something wrong. Thanks. Quote Link to comment Share on other sites More sharing options...
Hero999 Posted November 16, 2014 Report Share Posted November 16, 2014 After correcting liquidbytes's simulation, the steady state power dissipation in R6 is 3.9994µW. Quote Link to comment Share on other sites More sharing options...
Guest mourad3d Posted November 17, 2014 Report Share Posted November 17, 2014 After correcting liquidbytes's simulation, the steady state power dissipation in R6 is 3.9994µW.Ok, if you make accounts equal ability not be this problem Quote Link to comment Share on other sites More sharing options...
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