Jump to content
Electronics-Lab.com Community

Rheostat power rating


Kerrowman

Recommended Posts

It's interesting that you, in effect, got + and - 3.7kV across the output of the coil. That is certainly the sort of level I would expect, in which case I would expect more than the 3V I get when I attach my secondary to my load (water cell). Which brings me full circle to my earlier question, why am I getting only 3V across my water cell terminals when your simulation and your ignition coil experiments show much more?

Perhaps I should build a Tesla coil and zap my water cell with that?

As a square wave can be thought of a complex mix of different frequencies of sine waves (Fourier analysis) I think using a square wave in a transformer will result in higher losses at the higher frequency end so producing a rounded square wave output with some enhanced ripple. When that encounters the water cell that will undoubtedly modify the waveform but I haven't observed that yet.

 

Link to comment
Share on other sites


Your getting  just 3 volts suggest an impedance mismatch between the transformer and the cell.  In looking at using automobile ignition coils for high voltage I see a number of videos and articles where they get huge sparks from the coils that I can not get. I feel like you; where is the spark! I am thinking my coil is a dud!

See for example: https://www.youtube.com/watch?v=PTt5sM3moqQ  There are a number of similar videos there  using ignition coils for  high voltages.

Link to comment
Share on other sites

Thanks Harry,

I will certainly look into using ignition coils or perhaps a Tesla coil.

If it's a question of impedance matching then surely I only have the option to up the secondary coil's impedance. Given that at the moment its resistance is about 1 Ohm, then does it make sense to add a 1 MOhm resistor in series with it to bring it more in line with the 1.6 MOhm resistance of the water cell? Or will that not work or introduce other problems?

Julian

Link to comment
Share on other sites

There is something about pulse transformers dealing with the pulse width. If the input pulse width is two short
the current never has time to build up completely do to the lagging current in an inductor/coil. That would look like an impedance mismatch also.

If the pulse is to wide current is wasted when the coil is fully energized.

For example see  https://www.youtube.com/watch?v=vvXbTIqBY4o

Link to comment
Share on other sites

Hi Harry,

That makes sense but in the case of the ignition coil HV systems, like in the link you gave, they can operate at a similar frequency of say 200-500Hz and still give very powerful sparks so is the construction of an ignition coil, and also a flyback transformer, different to such a degree that they avoid this pulse width issue?

I'm inspired to build one or other of the attached, although the 555 based one has some useful duty and frequency adjustment. Maybe one of these will deliver 10+kV to my cell without significant losses?

Julian

Flyback HV Supply.jpeg

HV Ignition Coil Driver.jpeg

Link to comment
Share on other sites

  • 1 month later...

Hello friends. Very interesting topic you have here. You can model the electrodes underwater as an capacitor in parallel with a resistor (a leaky capacitor). Maybe this is why he used a bifilar coil... Bifilar coils are self resonant coils because of their capacitance. You can see this article here:

https://sci-hub.st/https://doi.org/10.1002/cta.2830

The autor proposed a resonant tank circuit without the capacitor, using only the capacitance of the bifilar coil.

If the electrodes underwater behave like a true capacitor, he wouldnt need 2 coils... Only one coil would do the job... Maybe the trick lies in the coils only...

Link to comment
Share on other sites

  • 2 months later...
On 4/29/2021 at 1:56 AM, uziao said:

Hello friends. Very interesting topic you have here. You can model the electrodes underwater as an capacitor in parallel with a resistor (a leaky capacitor). Maybe this is why he used a bifilar coil... Bifilar coils are self resonant coils because of their capacitance. You can see this article here:

https://sci-hub.st/https://doi.org/10.1002/cta.2830

The autor proposed a resonant tank circuit without the capacitor, using only the capacitance of the bifilar coil.

If the electrodes underwater behave like a true capacitor, he wouldnt need 2 coils... Only one coil would do the job... Maybe the trick lies in the coils only...

I appreciate your reply here. You tried your best to suggest the OP. I also want to know more about it. I would like to ask you an open question where do you usually try if you need a  professional essay writing service? Did you ever try to complete your project online https://studyclerk.com/? I'm going to try it for the first time. Thank you!

Link to comment
Share on other sites

  • 11 months later...

Yes, it's certainly the sort of level I'd expect. Which brings me full circle to my earlier question, why am I getting only 3V across my water cell terminals when your simulation and your ignition coil experiments show much more? I also need accounting assignment help which I browse  https://my-assignment.help/accounting-assignment-help/ site to finish the task. Keep it up!

Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
×
  • Create New...