Ivanlee Posted June 17, 2021 Report Share Posted June 17, 2021 Good day, all 🙂 Recently, I have a system running at 62V max, 54V nominal based on voltage divider rule formula. I wanted to have a little alert LED, so I was thinking about using 10, 1kohm resistors, and adding the LED bewteen the 9th and 10th (or 1st and 2nd, if it matters), to get at most 6V and just a few mA. Is a better/easier way? Is this a really crappy way? Or is this a perfectly fine way? 😶 Voltage Divider Basic and Rule.pdf Quote Link to comment Share on other sites More sharing options...
HarryA Posted June 17, 2021 Report Share Posted June 17, 2021 You can use one series resistor. See "Calculating an LED resistor value" at https://www.electronicsclub.info/leds.htm resistor =(supply voltage - LED voltage)/LED current = (62 - 2)/0.020 = 3000 ohms which is a standard resistor value. Quote Link to comment Share on other sites More sharing options...
Ivanlee Posted June 30, 2021 Author Report Share Posted June 30, 2021 Thank you for helping 🙂 I have a bunch of 1k, 1/4W resistors, so 10 of those will work fine. I guess that 6mA at 60V is only 360mW, which might be a bit high. I could always use a lot more resistors and experiment by reducing it until I get to a suitable brightness. Quote Link to comment Share on other sites More sharing options...
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