Electronics-Lab.com Community

# High voltage divider circuit to run an LED?

## Recommended Posts

Good day, allÂ ðŸ™‚
Recently, I have a system running at 62V max, 54V nominal based on voltage divider rule formula. I wanted to have a little alert LED, so I was thinking about using 10, 1kohm resistors, and adding the LED bewteen the 9th and 10th (or 1st and 2nd, if it matters), to get at most 6V and just a few mA.Â
Is a better/easier way? Is this a really crappy way? Or is this a perfectly fine way?Â ðŸ˜¶

##### Share on other sites

You can use one series resistor. See "Calculating an LED resistor value" at https://www.electronicsclub.info/leds.htm

resistor =(supply voltage - LED voltage)/LED current = (62 - 2)/0.020 = 3000 ohms which is a standard resistor value.

##### Share on other sites

• 2 weeks later...

Thank you for helpingÂ ðŸ™‚

I have a bunch of 1k, 1/4W resistors, so 10 of those will work fine. I guess that 6mA at 60V is only 360mW, which might be a bit high. I could always use a lot more resistors and experiment by reducing it until I get to a suitable brightness.

## Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

×   Pasted as rich text.   Paste as plain text instead

Only 75 emoji are allowed.

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.