You were right I was wrong
Seems I got Ohm's Law all wrong but nothing better to get the old books out again. At least you got me thingking again
What might have happened is that I have selected a value close to R14 but a bit higher which will give you a positive voltage on the base of Q1...
I really dont want to get in a argument about Ohm's law but my multimeter measure the 32v minus the 5,6V which gives you the 26.4.
What I said and measured is that Q1 was on with the values in the circuit diagram which pulled the output of U2 down which caused it to get hot!!!
So you have to...
I think your assumption about the voltage is wrong
If you messure with a voltmeter the voltage is 26,4 volts and not the too voltages together
If you make R13 a 46K then the voltage on Q1 is less than 0.6 volts to switch it on so it stays off
Only swithes on as the AC is removes as you say the...
Had the same problem with U2 getting hot
The voltage devider circuit (ResR13,R14)that is suppose to hold the Transistor Q1 off is keeping it on and thats why U2 is getting hot.
Get the voltage to the negative so that Q1 is off and only swithes on when AC is removed.
Problem solved