Recent content by XRZ

  1. X

    Non-changing current with C-EMF

    I was wondering about this diagram, if it would work. Kind of the same idea, however, current would not flow from the PS to the second slab.
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    Non-changing current with C-EMF

    Thank you @Merlin3189, much appreciated.
  3. X

    Non-changing current with C-EMF

    Well, the diagram that you used(of mine) seem to have increase opposition instead of canceling things. Also this site my help you, free schematic site that allows you to save it to you computer, I used it to create that diagram.
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    Non-changing current with C-EMF

    Thank you @Merlin3189, I'll study this and get back to you.
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    Non-changing current with C-EMF

    No. This whole thread had nothing to do with an electric motor, I just used it to an example to justify why I came up with my question, and yet we dove into that for some reason. That voltage can't be cancelled?
  6. X

    Non-changing current with C-EMF

    Well, I was wondering about Merlin3189's post: I'm questioning the possibility of such an example o_O, and I think the addition of another conductor would actually increase the induced current in opposition to the current source. I've attached some diagrams to show that.
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    Non-changing current with C-EMF

    What didn't you understand? I said a lot ;)
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    Non-changing current with C-EMF

    Im just trying to answer a question out of curiosity. I think the idea of the secondary conductor would not changing anything(but add more current in opposition). I don't see how by changing the wires it would actually cancel the other's induced EMF when there is power supply in the circuit. If...
  9. X

    Non-changing current with C-EMF

    How is this possible? A diagram: The first conductor and second, are in a changing magnetic field. From the diagram above it seems that they increase current in opposition while having the same induced counter EMF. Yet in this diagram without the PS, the cancel out: Of course both of them...
  10. X

    Adding voltage to a circuit?

    2 resistors in series that mean's 12/(1Ω + 1Ω) = 6A.
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    Adding voltage to a circuit?

    Got it, thanks.
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    Adding voltage to a circuit?

    Bear with me here, I'm starting to learn ohms law a bit better. What if the resistance is 1Ω and the voltage is 12V yet the power supply is 12W? The current can't be 12A... Does that mean current is equal to square root(12/1) ? And voltage too to equal 12W?
  13. X

    Adding voltage to a circuit?

    Right, and therefore that's wrong since ohms law must apply. But what if there are two power sources? One applying high current while the other just applies high voltage? And the circuit's demand current can be calculated from the resistance of the circuit. But what if the power supply or...
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    Non-changing current with C-EMF

    What's wrong? What don't I understand that seems to make no sense? I'm pretty sure you understood what I meant, but to a circuit it's nonsense?
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    Non-changing current with C-EMF

    Can't there be a secondary power source that just adds high voltage? A secondary power supply that has a high voltage and low current to deal with counter-emf.
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