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  1. chopnhack

    Excellent video on how electricity branches

    Always fascinated by the thought of how electrons move in a circuit, this man demonstrated using an o-scope - much dedication for probing what must have been a few hundred times!
  2. chopnhack

    Interesting Video on LED's

  3. chopnhack

    Hurricane Ian

    Hey all, Ian hit hard in South Florida. Let's all pray for our members down there. I have still to hear from one member in particular. I am hoping that they evacuated!!
  4. chopnhack

    Happy new year

    School/work/kids have kept me more than busy! No time for projects :-(
  5. chopnhack

    Happy new year

    Happy New Year all!!! (better late to the party than never ;-)
  6. chopnhack

    When did EP get so fancy?

    Hey all :-) Haven't been by in awhile and so quite a bit of a change to the format. Looks very professional, good job Ian!
  7. chopnhack

    How do I figure out what is jamming the RF signal in my garage

    If it was an issue with the remote while just in the vehicle I was going to mention that metallic film window tint sometimes decreases RF transmission... but as others have noted the issue is unclear and OP has not returned in two weeks - maybe they figured it out.
  8. chopnhack

    Ideas to start my project.

    Agreed, they do have pressure sensors in car seats, it is what is used to enable/disable the airbag in the front passenger seat of many vehicles. It's a shame the OP hasn't returned since January - the project is doable in parts and has some really good uses. I hope he hasn't given up...
  9. chopnhack

    PCB building

    Came out great Constantine! Was it your design also? What is it for?
  10. chopnhack

    Spring constant versus electric repulsion

    Thank you for helping me through that! I don't think I would have spotted that on my own.... physics is tricky!!
  11. chopnhack

    Spring constant versus electric repulsion

    I believe so, since the original length is 0.2m. It doesn't start exerting force until it is stretched beyond 0.2m. So it should be amended to y=120*(x-0.2m)? 14.4/x^2 = 120(x-0.2) x=0.569715m
  12. chopnhack

    Spring constant versus electric repulsion

    Two spherical point charges each carrying a charge of 40 mC are attached to the two ends of a spring of length 20 cm. If its spring constant is 120 Nm-1, what is the length of the spring when the charges are in equilibrium?
  13. chopnhack

    Spring constant versus electric repulsion

    I didn't assume that when I read the question. I took it as the spring is 20cm long when unstretched, then the charges are added.
  14. chopnhack

    Spring constant versus electric repulsion

    I think I have a lot more than two issues right now :mad::confused::p:D This seems like it needs to be solved by a system of equations. I was thinking of graphing the two against each other to see where they cross. first equation boils down to y = 14.4/x^2 the second equation is y = 120x. x...
  15. chopnhack

    Spring constant versus electric repulsion

    F = k ×(q1q2/r^2) 9x10^9 N×m2×C-2 × [(40μC^2)/3m^2] F=1.6x10^-6N this is the force of the two particles acting against each other the force of the spring at 3m stretch would be 360N I need to rethink this. Thanks for pointing that out! Knew it was too easy.
  16. chopnhack

    Particles in a Field

    Yes, but being that I took calculus so long ago, and did well in both sections they wouldnt let me take it again. I have to audit the courses at my own expense which I can not do until this fall. Luckily I was able to work through some derivations and integrals, simple stuff, but when I see a...
  17. chopnhack

    Spring constant versus electric repulsion

    Is this question this simple to answer? I feel like some of these questions are too easy....Makes me uneasy like I am missing something! Two spherical point charges each carrying a charge of 40 mC are attached to the two ends of a spring of length 20 cm. If its spring constant is 120 Nm-1, what...
  18. chopnhack

    Particles in a Field

    It makes sense after the fact, but its not intuitive. From the outset of the problem I would not have guessed that the time back would have been equal to the time to travel the first leg of the trip. The second leg's time would depend completely on the acceleration. If the field was stronger...
  19. chopnhack

    Particles in a Field

    For the first leg of the trip: Vi = the given 6.2x10^5 ms-1 Vf = 0 a = -5.95x10^12 ms-2 -6.2x10^5 ms-1 = -5.95x10^12 ms-2 * t divide by -5.95x10^12 ms-2 t = 1.04x10-7 sec to stop particle in the field Now the particle is repelled in the opposite direction. Since we have time we should...
  20. chopnhack

    Particles in a Field

    Two semesters in less than 12 weeks will do that.... The only one that I know of is Vf = Vi + a*t (that reads final velocity equal to initial velocity plus acceleration multiplied by time).
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