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  1. yousef_ob

    Study about GSM

    plz can anybody help me in making a study about GSM?? links wanted
  2. yousef_ob

    DSB power

    hello, fom the maths point of view this is forbidden because m(t) as shown is a function of time not a constant bye ;D
  3. yousef_ob

    DSB power

    thanx i solved it
  4. yousef_ob

    DSB power

    i think that you didnt noticed that the cos is multiplied by another time variable function so you cant integrate that simple. anyway thanx abt ur try
  5. yousef_ob

    DSB power

    thanx a lot. nice try!! i need a mathemetical solution.
  6. yousef_ob

    DSB power

    Hello, I thought that i give u the time to think in my quwstion. but to this moment i didnt get a solution to this problem. i hope someone will help me. bye
  7. yousef_ob

    DSB power

    hello, in the attached equation m(t) is a power signal - not an energy signal. we know that DSB modulation is defined by the equation m(t) cos (2*pi * fc*t). so that the power of this signal is the integration of the sequared equation over the period - i.e power = integration over period of...
  8. yousef_ob

    DSB power

    C'mon i have asked a question it wasnt a joke or a story. plz is there anyone could solve that for me??!! ???
  9. yousef_ob

    DSB power

    sure m(t) is the modualting power signal
  10. yousef_ob

    DSB power

    hello, plz could anyone solve this for me: in a DSB modulation if we assume that the modulating signal is a power signal, why this integration is zero, plz i want the mathemetical prove for the attached equation thanx very much
  11. yousef_ob

    Question from a student about amps

    hello about using dBs: we use dB because when we use dBs multiplication turns into addition as well as division turns into subtraction and this is very useful characteristic. and we can draw Bode plot which is a very helpful chart.
  12. yousef_ob

    Designing feedback amplifier

    HELLO, I AM SO SORRY, BUT I DIDNT GET IT YET!! CAN YOU EXPLAIN THE ATTACHED CICUITS TO ME?? PLEASE "I AM A BIGINNER.. FORGIVE ME" ???
  13. yousef_ob

    series/parallel circuits and dividers

    HELLO, YOU CAN USE THIS METHOD IN FINDING THE TOTAL RESISTANCE SEEN BY A VOLTAGE SOURCE. 1. AT THE TERMINALS OF THE VOLTAGE SOURCE NAME (a,b), THEN WHEN U FIND ANY RESISTANCE NAME ©, THEN GO ON d,e AND SO ON. 2. REDRAW THE CCT IN A NEAT FORM BY PUTTING THE LETTERS (a,b,c,d...) THEN SEE WHERE IS...
  14. yousef_ob

    Designing feedback amplifier

    HELLO, ABOUT YOUR COMMENT, YOU MAY BE WRONG BECAUSE IF YOU USE ONE +VE POWER SUPPLY THEN THE OP-AMP WILL NOT WORK PROPERLY BUT IT WILL SATURATE IN THE -VE REGION AND WE CANT GET A -VE O/P FROM THIS OP-AMP. WE WILL GET THE SAME THING IF WE USE A -VE POWER SUPPLY. THANX VERY MUCH
  15. yousef_ob

    Designing feedback amplifier

    HELLO VISHO, ABOUT UR AMPLIFIER CCT U DONT TAKE IN UR ACCOUNTS THE LOADING EFFECTS FROM THE FIRST STAGE TO THE SECOND STAGE. U WOULD BETTER USE TRANSISORS OTHER THAN OPAMPS, BECAUSE HERE U NEED ONE POWER SUPPLY BUT IN OP-AMP CCT U NEED TWO POWER SUPPLIES ONE -VE AND THE OTHER +VE. BUT THE...
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