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  1. C

    Power through current sources

    So the voltage across the two upper branches is 8V. Working through say the top branch, the voltage difference across the current source must be 8V-6V=2V. Hence P=IV = 2 X 4mA = 8mW. Why is my answer incorrect?
  2. C

    RL Circuit

    Hi everyone. I'm trying to find the i(t) for the circuit below. The correct answer is i(t) = -3.5 + 0.25e^(4t) I've managed to get the constant part but can't seem to get the exponential term. Can anyone see where I've gone wrong?
  3. C

    Different answer using inverting op-amp and KCL?

    If we forget about the inverting op-amp and just consider KCL. Why does that particular route of analysis give me +4.5V?
  4. C

    Different answer using inverting op-amp and KCL?

    I understand that +1.5V fed into the inverting op-amp will give an output of -4.5V. But using KCL at the ground node give me +4.5V, why is this?
  5. C

    Different answer using inverting op-amp and KCL?

    So what is wrong with my KCL calculation which gives V_0 = +4.5V?
  6. C

    Different answer using inverting op-amp and KCL?

    Hi all. I have a bit of an interesting problem (see attachment), I've calculated V_a in the first part of the question. Then I've applied KCL at the ground node to try and solve for V_0. I know that V_0 should be -4.5V due to the inverting op-amp being present but KCL gives me 4.5V? Thank you!
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