E
Eur van Andel
- Jan 1, 1970
- 0
Hi
I needed a circuit that converted a thermocouple (40 uV/K) to a 0..20mA input
of a PLC. Normal opamps can't touch the rails and I didn't like creating a
negative voltage. All I had was 24V DC. Here is my circuit:
(fixed pitch)
+24V DC +24V DC
| |
| |
+--------------------+
| | | |
| |\| 1k | |
+-|-\ ___ |/ |
| >--|___|--| |
/---------|+/ |> | 0.8 Ohm current output: 0..20mA
* |/| | | ___
\---------------+ +---+--|___|+->|-->|-->|--o--+
thermocouple | | | |
0..16mV | +--------------------+ .-. inside PLC:
0..400C | | | 250 Ohm to GND
| | |
| '-'
| |
| |
=== ===
GND GND
created by Andy´s ASCII-Circuit v1.24.140803 Beta www.tech-chat.de
The thermocouple generates about 16mv @ 400C (400*40uV), there is no
cold-junction compensation (with a working point of 300C, I don't need one).
The opamp tries to match the 16mv difference and raises its output. The NPN
boosts the current (if your opamp can't source 20mA) until 20mA*0.8Ohm = 16mV
over the resistor, which is fed back into the negative opamp input.
Most opamp outputs and inputs can't come near the rails and since it is current
output only, I added some diodes between the current measuring ressitor and the
PLC input. That way the thermocouple and the opamp in- & outputs are raised far
enough from the bottom rail.
The 1k is a currrent limiting resistor to protect the NPN transistor.
Measure the polarity of the thermocouple while holding it in a flame.
I needed a circuit that converted a thermocouple (40 uV/K) to a 0..20mA input
of a PLC. Normal opamps can't touch the rails and I didn't like creating a
negative voltage. All I had was 24V DC. Here is my circuit:
(fixed pitch)
+24V DC +24V DC
| |
| |
+--------------------+
| | | |
| |\| 1k | |
+-|-\ ___ |/ |
| >--|___|--| |
/---------|+/ |> | 0.8 Ohm current output: 0..20mA
* |/| | | ___
\---------------+ +---+--|___|+->|-->|-->|--o--+
thermocouple | | | |
0..16mV | +--------------------+ .-. inside PLC:
0..400C | | | 250 Ohm to GND
| | |
| '-'
| |
| |
=== ===
GND GND
created by Andy´s ASCII-Circuit v1.24.140803 Beta www.tech-chat.de
The thermocouple generates about 16mv @ 400C (400*40uV), there is no
cold-junction compensation (with a working point of 300C, I don't need one).
The opamp tries to match the 16mv difference and raises its output. The NPN
boosts the current (if your opamp can't source 20mA) until 20mA*0.8Ohm = 16mV
over the resistor, which is fed back into the negative opamp input.
Most opamp outputs and inputs can't come near the rails and since it is current
output only, I added some diodes between the current measuring ressitor and the
PLC input. That way the thermocouple and the opamp in- & outputs are raised far
enough from the bottom rail.
The 1k is a currrent limiting resistor to protect the NPN transistor.
Measure the polarity of the thermocouple while holding it in a flame.