flippineck
- Sep 8, 2013
- 358
- Joined
- Sep 8, 2013
- Messages
- 358
I bought a dinky little DC to DC boost converter on ebay. It has a twin screw terminal input block, and a twin screw terminal output block.
The listing says it will accept a DC input of something like 10 to 60 VDC, and output anything from 12 to 80 VDC.
On the board, there are two trim pots. One is labelled 'voltage adjust', and one is labelled '(input) current adjust'.
The board is populated with a large 2-pin toroidal inductor, several large value electrolytics, two eight-pin SMT IC's, and 3 three-pin IC's which look like black, rectangular, bolt-to-a-heatsink via a tab type power transistors. Amongst a bunch of smaller assorted SMT components. It's a rectangular board say 2 inches by 3, and the whole thing is mounted on a decent stonking black aluminium heatsink.
What I can't figure out is, I'm thinking, the load is going to present a basically constant power requirement in stable operation? so, why do I need a trim pot for 'input current adjust'?
Here is the unit: http://www.ebay.co.uk/itm/310705571577
I was expecting that, once I set the output voltage with the load connected, with a constant input voltage, wouldn't the input current just look after itself? a la P=IV & V=IR? why would I want to try and alter the current away from what the load 'wanted' to take?
I must be missing something in my thinking..?
BTW although this boost converter is designed as a general purpose module (i think), my own specific application is to take the 12V output from a car battery, and run an LED rated at 32V from it. Maybe my own simple application is colouring my thinking.
The listing says it will accept a DC input of something like 10 to 60 VDC, and output anything from 12 to 80 VDC.
On the board, there are two trim pots. One is labelled 'voltage adjust', and one is labelled '(input) current adjust'.
The board is populated with a large 2-pin toroidal inductor, several large value electrolytics, two eight-pin SMT IC's, and 3 three-pin IC's which look like black, rectangular, bolt-to-a-heatsink via a tab type power transistors. Amongst a bunch of smaller assorted SMT components. It's a rectangular board say 2 inches by 3, and the whole thing is mounted on a decent stonking black aluminium heatsink.
What I can't figure out is, I'm thinking, the load is going to present a basically constant power requirement in stable operation? so, why do I need a trim pot for 'input current adjust'?
Here is the unit: http://www.ebay.co.uk/itm/310705571577
I was expecting that, once I set the output voltage with the load connected, with a constant input voltage, wouldn't the input current just look after itself? a la P=IV & V=IR? why would I want to try and alter the current away from what the load 'wanted' to take?
I must be missing something in my thinking..?
BTW although this boost converter is designed as a general purpose module (i think), my own specific application is to take the 12V output from a car battery, and run an LED rated at 32V from it. Maybe my own simple application is colouring my thinking.
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