Okay, I have looked for a circuit and found this:
http://www.ti.com/lit/an/slva139/slva139.pdf
The MOSFET is being put in backwards from it's usual usage, i.e. with an N-MOSFET the drain is connected to the battery - and the source to the load. Normally, you would not do this because the body diode would conduct and you could never turn it off. But in this clever usage, when the battery is backward neither the body diode nor the MOSFET will conduct, and with the battery connected the gate will be at the battery + voltage and the source near the battery - voltage, which makes it conduct, shorting the body diode and having a much smaller voltage drop than a diode would.
No pulldown resistor is needed, because when the battery is right, the gate is always connected to b+ and when the battery is backwards it is connected to battery -. It can never float.
Bob