Array in ascending order

[vead]

Hello

I am looking help to understand this program.

array in ascending order in C programming

#include <stdio.h>
 
int main(void)
{
    int a[20], i = 0, j = 0, n, t;
 
    printf ("\n Pramot user to Enter Element: ");
    scanf ("%d", &n);
    printf ("\n");
 
    for (i = 0; i < n; i++)
    {
        printf ("\n Enter the %dth element: ", (i+1));
        scanf ("%d", &a[i]);
    }
 
    for (j = 0 ; j <(n-1); j++)
    {
        for ( i = 0 ; i <(n-1) ; i++)
        {
            if (a[i+1] < a[i])
            {
                t = a[i];
                a[i] = a[i + 1];
                a[i + 1] = t;
            }
        }
    }
 
    printf ("\n Ascending order: ");
    for (i=0 ; i<n ; i++)
    {
        printf (" %d", a[i]);
    }
 
 
      return 0;
}

I don't understand this part of program

    for (j = 0 ; j <(n-1); j++)
    {
        for ( i = 0 ; i <(n-1) ; i++)
        {
            if (a[i+1] < a[i])
            {
                t = a[i];
                a[i] = a[i + 1];
                a[i + 1] = t;
            }
        }
    }

 

[(*steve*)]

Do you understand "for" loops?

 

[vead]

Do you understand "for" loops?

Yes I understand use of "for" loop

#include <stdio.h>
int main (void)
{
   int N = 10;
   int i; 
   for (i=0; i<N; i++)
   {
     printf ("Number %d \n",i);
   }
  
   return 0;
}

Number 0
Number 1
Number 2
Number 3
Number 4
Number 5
Number 6
Number 7
Number 8
Number 9

 

[Harald Kapp]

I don't understand this part of program

Look up bubblesort.

 

[(*steve*)]

So, what does this do?

for (j = 0 ; j <(n-1); j++)

 

[vead]

So, what does this do?

for (j = 0 ; j <(n-1); j++)

It check the value n-1 value then print the value of j

#include <stdio.h>

int main()
{
   int j, n;
  
   printf("value of n : ");
   scanf("%d", &n);
  
   for (j = 0 ; j <n-1; j++)
          
    printf(" j : %d \n",j);
          
    return 0;
}

value of n : 4
j : 0
j : 1
j : 2

 

[(*steve*)]

No, just the for statement. Do you understand it?

What do the three parts of the for statement do?

 

[vead]

No, just the for statement. Do you understand it?

What do the three parts of the for statement do?

I was showing you that I understand what is "for (j = 0 ; j <(n-1); j++)"

I am stuck in three parts of the for statement. I don't know what is use of them ?

 

[(*steve*)]

Hi I'm that case you clearly don't understand.

Research the c for statement and come back when you have learned what they do.

Trying to claim you understand when you only have the vaguest notion is another example of your penchant for trying to run before you can walk.

There are no short cuts. Stop trying to take them.

 

[vead]

Hi I'm that case you clearly don't understand.

Research the c for statement and come back when you have learned what they do..

Where do you find wrong me in my understanding ?

Here loop run 5 times , first it set to 0 than increase by 1 until it get 4 and then stop

#include <stdio.h>

int main (void)
{
   int N = 5;
   int i;
   for (i=0; i < N; i++)
   {
     printf ("Number = %d \n",i);
   }
 
   return 0;
}

Number = 0
Number = 1
Number = 2
Number = 3
Number = 4

N-1 = 5-1 = 4
So N = 4
Here loop run 4 times , first it set to 0 than increase by 1 until it get 3 and then stop

#include <stdio.h>

int main (void)
{
   int N = 5;
   int i;
   for (i=0; i < N-1; i++)
   {
     printf ("Number = %d \n",i);
   }
 
   return 0;
}

Number = 0
Number = 1
Number = 2
Number = 3

 

[(*steve*)]

But what do the the parts mean?

So far all I can see is that you've written some code and explained what it did.

The fact that you can't understand the original code is evidence you don't understand the c statements it uses.

If you understand the for statement

For (a; b; c)
{
d;
}

Then you can trivially give the mapping of a,b,c, and d to w, x, y, and z below

z;
While (y)
{
x;
w;
}

 

[vead]

I have make it simple

#include <stdio.h>
 int main(void)
{
    int a[10], i, j, n, temp;
 
    printf ("\n Pramot user to Enter size: ");
    scanf ("%d", &n);
   
      for (i = 0; i < n; i++)
      {
        printf ("\n Enter the  element: ");
        scanf ("%d", &a[i]);
      }
   
       for(i=0;i<n;i++)
      {
     
        for( j=i;j<n;j++)
        {
                if(a[i]>a[j])
                {
                        temp=a[i];
                        a[i]=a[j];
                        a[j]=temp;
                }
        }
       
      }
     
      for(i=0;i<n;i++)
             
      printf("%d ",a[i]);
   
 
      return 0;
}

Pramot user to Enter size: 4

Enter the element: 1

Enter the element: 9

Enter the element: 2

Enter the element: 5

1 2 5 9

 

[Harald Kapp]

Read my post #4 and follow the link.
Look at your input and output and compare to what is explained in the link.

 

[vead]

Read my post #4 and follow the link.
Look at your input and output and compare to what is explained in the link.

I followed that link and wrote program in Post #11

 

[Harald Kapp]

I followed that link and wrote program in Post #11

Do you understand how the program works? It is described in the linbk and the descriptin imho answers the question about the nested for loops.

 

[vead]

Do you understand how the program works? It is described in the linbk and the descriptin imho answers the question about the nested for loops.

Yes i understand how it works

 

[(*steve*)]

Yes i understand how it works

Great, even though I don't necessarily entirely believe you, this thread can now be closed.

 

[Brian Griffin]

Before closing it down, here's the whole thing about Bubble-sorting:

https://www.geeksforgeeks.org/bubble-sort/

This is very straightforward! Nothing can be simpler than this!