Because Q1, if in sat, pulls up the first diode so the V at junction of
first diode cathode is ~ 5 - { .7 (diode) + .2 (Vsat) } =~ 4.1V. That
is not low enough to get Q2 and its base diode turned on, turned
on hard. You would need the second diode and Vbe Q2 turned
on which is ~ .7 + .7 =~ 1.4V...