Vo(0+) occurs after the input voltage, Vi, transitions from 0 to E. At time Vo(0+), Vi = E. Vo(0+) will then be Vi R1/(R1+R2), assuming C1 is fully discharged at Vo(0). So the first part of your answer is correct.
Vo will rise exponentially to toward Vi = E until at Vo(∞) = Vi = E. So the...