Calculating draw current

[roughshawd]

If my transformer bottoms out at half an amp with a full load of 35v, how did I calculate the load capacity of the transformer at 6v?

 

[Bluejets]

Assuming two secondaries.......
35 * 0.5 = 17.5va.
17.5va /6 = 2.9a

 

[roughshawd]

How about this.. heh heh?!, a lossy signal at 35v and .5 amps will have how many amps when it reaches 6 v ??? Or... If 35v has .5 amps in an induced current, how much amperage will it have at 6v?!

That was great! Thanks, you could have just said "ohms law", and called me an idiot. Thanks brains ..

How many watts did the old digital movie cameras use?

More math. Yeah!!!

About 12.8w if the battery is fully charged at 6v 1800ma...

You must have something before you can change it... Is there a word for this activity????!!! Heh!

 

[Alec_t]

17.5va /6 = 2.9a

.... providing the secondary winding resistance is insignificant.
But suppose it were 1 Ohm. At 0.5A it would drop only 0.5V, which might be acceptable; but at 2.9A it would drop 2.9V, i.e.nearly half the voltage you want.

 

[Bluejets]

Well, you have to admit, the question was rather broad in nature for any reasonable response.