charger for Cordless phone battery.

fever16

Mar 12, 2006
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hi all
iam working on a school LED project.where we need to use a 3.6v 300ma battery(one used in cardless phones).u know cordless phone chargers are dumb type.can u suggest me some good charger for this battery pack.
i don't want  hi-fi type of charger.just simple one which makes the battery last for long times without destroying it.and if it got some indictor it would be great.
thanks in advance



 

ante1

Jan 24, 2004
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Hi fever,

Welcome to our forum,

You could use an LM317 setup as a constant current regulator at 15mA and just leave it on 24/7!

 

fever16

Mar 12, 2006
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thanks ante

is it possible to make some simple moniter type.imean which got atleast indictor(imean lighting up an LED when charging done) using some transistor like..

 

ante1

Jan 24, 2004
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Hi fever,

You wanted a simple one, just leave it on and the pack will always be full when you need it. If you go for a “ready LED” circuit things starts to get complicated.

 

fever16

Mar 12, 2006
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ohh ok then
i did a small search on net and i found below 2.which one of this is best.

http://agendawiki.com/cgi-bin/aw.pl?ChargingCircuits

aaapulsechargerckt8cd.png

this one from our forum only.

and this is from groups-google-
trickler.gif

what is ur openion abt these

 
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ante1

Jan 24, 2004
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Hi fever,

This is from the LM117/317 datasheet; R1 should be 82 Ohm and you put the pack where it says load! You can power it from any DC-wallwart  9 – 25VDC.  ;)

View attachment 38670

 

fever16

Mar 12, 2006
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thanks ante.i'll go with lm317 based circuit

i dono much abt these abt these rechargbles.but i think ni-cd shld be chrged at 1.5+pack voltage and c/10 of its current rating it.
if it is true then i need 5.1v @ 30ma for 14Hr .

 

audioguru2

Apr 6, 2004
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fever16 said:
i dono much abt these abt these rechargbles.but i think ni-cd shld be chrged at 1.5+pack voltage and c/10 of its current rating it.
if it is true then i need 5.1v @ 30ma for 14Hr .
I don't know where you learned the wrong voltage formula.
Each cell will charge to 1.4V to 1.5V. Therefore the 3-cell battery will be 4.2V to 4.5V when fully charged.
The LM3117 needs at least 2V across it and the current-sensing resistor has a 1.25V drop, so the minimum input voltage to the circuit is 7.75V.
 

fever16

Mar 12, 2006
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thanks for correcting me.
is current calculation is right(c/10 for 14Hrs)

if yes then the final result will be 7-8v input to LM317 with R1 82Ohms resistor.(as ante said) can charge a 3.6v battery pack safely in 14Hrs

 

audioguru2

Apr 6, 2004
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fever16 said:
is current calculation is right(c/10 for 14Hrs)?
Yes, if the battery is rated for 300mA/hrs.

if yes then the final result will be 7-8v input to LM317 with R1 82Ohms resistor.(as ante said) can charge a 3.6v battery pack safely in 14Hrs
No. 7V is too low. "The  minimum input voltage to the circuit is 7.75V."
 

ante1

Jan 24, 2004
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Hi Guys,

Yes 7 volts is too low, that’s why I said “You can power it from any DC-wallwart  9 – 25VDC.”! ;D

 

fever16

Mar 12, 2006
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got it.
thanks.

is there any particular formula for this resistor value.
imean in furture if i want to charge packs of 700ma or 800ma etc i need to change resistors too right.

and gyus to charge AA or AAA "single cell" what modification shld be done in  lm317 design.

 

ante1

Jan 24, 2004
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The voltage drop across R1 is always 1.2Volts (controlled by the regulator), using (I = U / R )you get the charge current.
Example; 1.2 V / 82 Ohm =  0.0146 A that means about 15 mA!
If you increase the charge current to 800mA you need a heatsink for the LM317!
Got it? ;D

 

fever16

Mar 12, 2006
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as per c/10 for 14Hr rule,current for charging a 300ma battery shld be 30ma. right.
but in previous post u said 82 Ohms resistor will work.where as it shld be 40 Ohms for 30ma 
correct me if iam wrong
iam bit confused ???

 

ante1

Jan 24, 2004
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Hi fever,

That’s correct for C/10 but I suggested 15mA so that you could leave the pack unattended for an “unlimited” period of time. If you like you can add another 82 Ohm resistor in parallel to have C/10 – 14 h charge. I made a drawing for you, if you leave the switch open its C/20 if closed it’s C/10.
If you don’t need the C/20 setting just omit the switch. The reason for two resistors is that it’s not easy to find a 40 Ohm resistor but two 82 in parallel is 41 Ohm and that is just fine. 8)

View attachment 38693

 

fever16

Mar 12, 2006
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cool.
thanks a lot ante.
tomorrow i'll get some resistors of different values.so that i can make it variable.
imean 15ma-c/20
          30ma-c/10 for 14Hr
          60ma-c/5  for 7Hrs (ofcourse not preferable)
thanks once again.for helping me
u ppl are just really amazing .  :-*

 
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