Help with phasors please

[Circuits]

 

[Alec_t]

Welcome to EP!
This is a Homework Help forum, not a Homework-done-for-you one. Please post your best effort so far at solving this.

 

[Circuits]

I actually have this solution but I failed to understand it

 

[dorke]

What is it that you don't understand?

1s line is current divider rule applied.
2nd line is KCL applied.
3rd line is KVL applied.

 

[Circuits]

Welcome to EP!
This is a Homework Help forum, not a Homework-done-for-you one. Please post your best effort so far at solving this.

What is it that you don't understand?

1s line is current divider rule applied.
2nd line is KCL applied.
3rd line is KVL applied.

I am familiar with the current divider rule but I don't understand how it was applied to obtain the term -j6/8+j6-j6. And then also how to they reach to an angle of 90. The 2nd and 3rd lines I get. Thank you for replying

 

[dorke]

1. Find Z1 and Z2 and apply the current divider rule,it is trivial.
2. -j is -90 degrees.

 

[Ratch]

I am familiar with the current divider rule but I don't understand how it was applied to obtain the term -j6/8+j6-j6. And then also how to they reach to an angle of 90. The 2nd and 3rd lines I get. Thank you for replying

Because you have probably handed in your homework, here is the phasor diagram. Notice that I = I1 + I2 .

Ratch