J
John Woodgate
- Jan 1, 1970
- 0
I read in alt.binaries.schematics.electronic that Tim Williams
Since my equation shows K2O being formed, I don't see what you doubt.
The 'gas' in this case is H2O. K2O doesn't 'burn' in air but it *might*
attract more oxygen to form KO2.
Doubtful to me, since gas is escaping all the while. I don't know if
K2O burns in air, but K metal (still hot) certainly does.
Since my equation shows K2O being formed, I don't see what you doubt.
The 'gas' in this case is H2O. K2O doesn't 'burn' in air but it *might*
attract more oxygen to form KO2.