Another way to write τ>>t would be t<<τ or t=0+ for initial start-up or turn-on of the circuit.
But a capacitor doesn't know if it is in a LPF or HPF, it just behaves according to the defining equation Ic=Cd/dtVc. So at t=0+ the voltage across the capacitor is zero (and rising) but the current through the capacitor and the rate of change of the voltage across the capacitor are determined by other components in the circuit.
At t=0+ there is current flowing through the component and no voltage across the component. Would you call that a short circuit?
That kind of thinking is so mired in the time domain. Linear circuit theory is based in the complex-frequency domain where capacitive current obeys Ohm's Law. However, the circuits in the complex-frequency domain are the Laplace transform of their counterpart in the time domain. While time domain explanations are certainly true, they lack the conceptual simplicity of the complex-frequency domain where circuit analysis is done on the other side of the Laplace transform, and capacitive current does flow through its transformed counterpart from the time domain. I graduated from the time domain a long time ago, and I'm not going back (except through the inverse Laplace transform).Keep in mind that current does not pass through a capacitor.
That kind of thinking is so mired in the time domain. Linear circuit theory is based in the complex-frequency domain where capacitive current obeys Ohm's Law. However, the circuits in the complex-frequency domain are the Laplace transform of their counterpart in the time domain. While time domain explanations are certainly true, they lack the conceptual simplicity of the complex-frequency domain where circuit analysis is done on the other side of the Laplace transform, and capacitive current does flow through its transformed counterpart from the time domain. I graduated from the time domain a long time ago, and I'm not going back (except through the inverse Laplace transform).
Hi, I have a question about LPF and HPF in RC circuit.
I know that in LPF when τ>>t the capacitor is close to be a short.
but what happens in HPF when τ>>t ? that capacitor is close to be a short also?
Thanks for your help!
If you Laplace transform a capacitor, whaddya get? Actually though, linear circuit analysis is not concerned with the physics of electrical components. What we call a 'capacitor' is just a model of a one-port network where current flowing through the network behaves according to the differential equation Ic=Cd/dtVc. It makes no sense to discuss the device physics of this 'capacitor' since it is just a mathematical model labeled 'capacitor'.Both time and frequency analysis are mathematical methods which do not supplant the physics of circuits containing electrical components.
That is why we maintain consistency and say that current flows through a capacitor.Whether the charge passes through components like inductors and resistors, or accumulates and depletes on the plates of a capacitor makes no difference in analyzing the current existence in the component branch of the circuit.
You are the only one saying "charge passes through a capacitor."For either method, it is wrong to say that charge passes through a capacitor.
Indeed, there is a whole world full of these folks. You should discuss your complaint with them.A lot of folks are calling the relationship of impedance, voltage, and current by the wrong name.
That may be how Georg Ohm characterized his work when he first published his empirical findings in 1827, but what we call "Ohm's Law" has been reformulated numerous times since then and Georg Ohm wouldn't even recognize it today, especially Ohm's Law for AC.V=I R is not Ohm's law. Ohms law is a property of a material (electrical linearity)
I'm sure the feeling will be mutual.I will be happy to discuss this with anyone.
If you Laplace transform a capacitor, whaddya get? Actually though, linear circuit analysis is not concerned with the physics of electrical components. What we call a 'capacitor' is just a model of a one-port network where current flowing through the network behaves according to the differential equation Ic=Cd/dtVc. It makes no sense to discuss the device physics of this 'capacitor' since it is just a mathematical model labeled 'capacitor'..
That is why we maintain consistency and say that current flows through a capacitor..
You are the only one saying "charge passes through a capacitor.".
Indeed, there is a whole world full of these folks. You should discuss your complaint with them..
That may be how Georg Ohm characterized his work when he first published his empirical findings in 1827, but what we call "Ohm's Law" has been reformulated numerous times since then and Georg Ohm wouldn't even recognize it today, especially Ohm's Law for AC.
I'm sure the feeling will be mutual.
That is just plain false. Oliver Heaviside demonstrated how to treat the current flowing through a capacitor exactly the same as current flowing through a resistor. This concept is fundamental to linear circuit theory.Any capacitor model has to acknowledge a discontinuity of current in a capacitor. Otherwise, the capacitor would just be a resistor
You are still the only one here talking about charge through a capacitor.No, I am saying that charge does not flow through a capacitor.
As one of the illustrious members of our community once said: "Skin that smoke wagon, and see what happens!"You are one of those folks. Therefore, I am calling you on it.
You seem to think that "Ohm's Law" must exactly reflect what Ohm published in 1827, but in fact we can attach that title to anything we want. No immutable law has been broken. So your premise is false, and your argument is therefore invalid.Physical laws are based on physics, and are immutable. Therefore, they can not be changed or reformulated unless they are incorrectly stated in the first place.
Throw down, boy! Or are you just going to stand there and bleed?Bring them on!
That is just plain false. Oliver Heaviside demonstrated how to treat the current flowing through a capacitor exactly the same as current flowing through a resistor. This concept is fundamental to linear circuit theory.
Note that I posted some of Heaviside's work on that topic a while back. But our illustrious moderators seemed to think it was inappropriate for this site, and removed it. So if you missed it then, you missed out and I'm not going to post it again.
You are still the only one here talking about charge through a capacitor.
As one of the illustrious members of our community once said: "Skin that smoke wagon, and see what happens! Throw down, boy! Or are you just going to stand there and bleed?
You seem to think that "Ohm's Law" must exactly reflect what Ohm published in 1827, but in fact we can attach that title to anything we want. No immutable law has been broken. So your premise is false, and your argument is therefore invalid.
Since you insist on misinterpretation, I'd say that is your problem - not mine.You talked about "current through the capacitor" in post #2 of this thread. Since current is the rate of charge flow, you, yourself, effectively said that charge is flowing through a capacitor.
Since you insist on misinterpretation, I'd say that is your problem - not mine.
I keep trying to explain how to interpret that statement, but you keep insisting your misinterpretation is paramount.I don't know how else what you said could be interpreted ...
I keep trying to explain how to interpret that statement, but you keep insisting your misinterpretation is paramount.
This is a clue about linear circuit theory for those who may aspire to advanced study of network analysis and synthesis. Device physics are not relevant to circuit analysis. What is important are network models and the mathematical description of electrical characteristics at the network ports. For instance, as described above, a capacitor is a one port network model where a differential equation defines the relationship between the current flowing through the port and the voltage across the port. That is all. Device physics is another discussion, but not this one. Those who speak of current flowing through the network model of a 'capacitor' do not wish to be dragged into a discussion of capacitor device physics. How can you tell who those individuals are? They'll be the ones talking about circuit theory.
Then please show from the defining differential equation Ic=Cd/dtVc that current does not flow through the capacitor network model.A capacitor has its unique and particular differential equation description due to its property of not allowing any electrical charge to flow through its dielectric.
Then please show from the defining differential equation Ic=Cd/dtVc that current does not flow through the capacitor network model.
You have changed the question from one of current flowing through a network model to the issue of charge movement in the physical approximation of the network model. Since you did not answer the original question, you get zero points for that response.Now, if the charge passed through the capacitor,...
You have changed the question from one of current flowing through a network model to the issue of charge movement in the physical approximation of the network model. Since you did not answer the original question, you get zero points for that response.
You have changed the question from one of current flowing through a network model to the issue of charge movement in the physical approximation of the network model. Since you did not answer the original question, you get zero points for that response.
I understand what you did, and that is why I know you failed. When asked to analyze the network model of a capacitor, you immediately jump to the physical approximation of the capacitor network model and analyze that instead. The reason you fail is that you wear blinders that keep you from correctly seeing the problem. It is as though your worldview looks like this:If you cannot understand that, I don't know to explain it better.
I understand what you did, and that is why I know you failed. When asked to analyze the network model of a capacitor, you immediately jump to the physical approximation of the capacitor network model and analyze that instead. The reason you fail is that you wear blinders that keep you from correctly seeing the problem. It is as though your worldview looks like this:
View attachment 20294
When analyzing the network model of a capacitor one needs to turn off their view of device physics and see the linear circuit theory view instead:
View attachment 20293
Notice that the network model has no plates and no dielectric material, it just has a differential equation. So the DF is all you have to work with. Also note that the behavior of the network model of a capacitor is defined in terms of the current flowing through the capacitor. So it is no surprise that you don't know how to explain it better. And that is why those who discuss linear circuit theory are correct when referring to current flowing through a capacitor.