Hi
OK, so i'm a complete novice at this electronics stuff and need a little help with something here.
Here's what i want to do:
I have a 2-way radio that i wish to power off a motorcycle battery [for use whilst riding so i can talk to other bikers], instead of using the Nicd battery that came with the radio.
But - i have conflicting info on how to do this.
The facts:
Motorcycle battery = 12V [or as close as you get with a vehicle battery]
2-way radio requires max 4.5V 500mA [Nicd battery supplied = 3.6V]
The solution:
Run wire off 12V battery terminals to 2-way radio terminals and reduce voltage using resistor.
The problem:
OK, so this is the part i have a problem with. I am given conflicting info from two people on how to work this out.
opinion 1
I must first subtract the voltage required by the radio from the source, and use the remainder to find the resistor value required - ie:
12V - 4.5 = 7.5 / .5 = 15ohm
... and power rating:
7.5 * .5 = 3.75W
requiring 15ohm 3.75W resistor to power 2-way radio from motorcycle battery
opinion 2
No need to subtract the voltage required by the radio and the resistor required as follows:
12V / .5 = 24ohm
... and power rating:
12 * .5 = 6W
requiring 24ohm 6W resistor to power 2-way radio from motorcycle battery
--------
Can some kind person please shed some light on this?
Thanks
detrjo
OK, so i'm a complete novice at this electronics stuff and need a little help with something here.
Here's what i want to do:
I have a 2-way radio that i wish to power off a motorcycle battery [for use whilst riding so i can talk to other bikers], instead of using the Nicd battery that came with the radio.
But - i have conflicting info on how to do this.
The facts:
Motorcycle battery = 12V [or as close as you get with a vehicle battery]
2-way radio requires max 4.5V 500mA [Nicd battery supplied = 3.6V]
The solution:
Run wire off 12V battery terminals to 2-way radio terminals and reduce voltage using resistor.
The problem:
OK, so this is the part i have a problem with. I am given conflicting info from two people on how to work this out.
opinion 1
I must first subtract the voltage required by the radio from the source, and use the remainder to find the resistor value required - ie:
12V - 4.5 = 7.5 / .5 = 15ohm
... and power rating:
7.5 * .5 = 3.75W
requiring 15ohm 3.75W resistor to power 2-way radio from motorcycle battery
opinion 2
No need to subtract the voltage required by the radio and the resistor required as follows:
12V / .5 = 24ohm
... and power rating:
12 * .5 = 6W
requiring 24ohm 6W resistor to power 2-way radio from motorcycle battery
--------
Can some kind person please shed some light on this?
Thanks
detrjo