It is lonly logical.
If they use a 10 bits ADC, then for a max of 2 kW the miniumum is already 2 W.
Add any offset in the current sensing, or even one bit eror,
and you are at a minium of 4 W etc etc.
What exactly are you trying to measure, real power or apparent power ?
Is it assumed that the current (and/or voltage) looks like a sine
wave?
While a constant amplitude clean sinusoid voltage connected to a pure
resistive load will produce an in-phase sinusoid current, measuring
the peak current (and assuming nominal voltage) could be used to give
some real power indication. Measuring the current with 10 bit ADC
could give a 1000:1 power range (such as 2 kW:2 W).
Any load with some reactive components would cause a phase shift
between voltage and current and the simplistic system would only
produce the apparent power. Any rectifiers would create a large peak
to average current ratio, so the 1.41:1 peak/rms ratio for a sinusoid
is no longer valid.
For real power, you must multiply the instantaneous voltage with the
instantaneous current and average out. This can be done by an analog
multiplier followed by analog averaging before the ADC or use separate
ADCs for current and voltages sampled at a high frequency and do the
multiplying and averaging in digital domain.
With rectifier loads, the peak current can be quite high, often much
higher than the fuse ratings and the harmonics on the voltage can
cause long duration peaks higher than the fundamental frequency. Thus
the signal conditioning, multiplication and averaging require a quite
large dynamic range, regardless if the most processing is done in
analog or digital domain.