transformer connected to half wave rectifier circuit with 50 ohms load
given
primary turn Np = 5
secondary turn Ns=1
peak voltage Vp= 220
Do you mean
primary voltage Vp = 220V AC RMS?
Or does "peak voltage Vp" mean the
peak voltage at the primary?
If it means the peak primary voltage, you should convert it to an RMS voltage, then do the rest of the calculations using RMS voltages, because in circuits using sine waves, AC voltages are normally expressed as RMS voltages.
load Rl= 50 ohms
find out unknown value
primary voltage ?
They are probably asking for the primary voltage in VAC RMS.
secondary voltage ?
I dc current ?
I ac current ?
peak current ?
my effort
formula
Np/NS=V1 / V2
5/1=220/V2
V2= 44 volt Ac
That's the right idea, but if the primary voltage is 220V
peak, that will be wrong. A voltage of "44 volts AC", without any other information, means 44V AC
RMS (root mean square). This is not a peak voltage. If the 220V primary voltage is actually the
peak primary voltage, you need to convert that to an RMS voltage first. Then you can work through the calculations again using RMS values everywhere.
how to determine I dc current I ac current ?
DC current will be zero because the positive current on the positive half-cycles is balanced by the negative current on the negative half-cycles. Unless I'm missing something. I think that's a bit of a trick question.
You can calculate the RMS current in the secondary using Ohm's Law if you know the RMS voltage across the secondary and the load resistance.
Once you know the RMS current in the secondary, you can calculate the peak current.
