Ken Smith said:
So what is lowering the gain? If the gain doesn't decrease, the signal
will continue to build up.
Sounds like it's set exactly right...
I think you're making an error along the lines of Tesla: resonances aren't
unlimited. Jim said the Q is known and the drive is known, so you get a
voltage divider between the Thevenin output impedance of the amplifier and
the resistive loss component in the tank. For constant current drive it's
even simpler, V = I*R.
Such a circuit could be hard to start, but a hysteretic drive should do it
quite nicely. Although, gain is then very large (indeed, greater than
infinity, so to speak, due to the positive feedback in excess of the open
loop gain), so it must be limited by the driver stage. In that case, the
output impedance (to the tank) is limiting it, with much harmonic content of
course, which is mostly attenuated, depending on Q.
Tim