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prateeksikka

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Posts posted by prateeksikka

  1. HI ALUN!
    thats what i said ,the power meters only measure the power used by us i.e the power dissipated in the resistive elements at our homes.If we have pure inductances we need to pay nothing as we are dissipating nothing!
    any explanation for the fallacy?
    :(

  2. hi there!
    YEAH TOO SMALL FOR A PILOT TO SEE.AUDIOGURU,WHAT KIND OF DAMPING ARE U TALKING ABOUT?
    DO U EXPECT SUCH HEAVY LINES CARRIED AWAY BY AIR,YEAH MAY BE THEY CAN SWING A BIT UPON HEAVY WINDS.HEY,CAN IT HAVE A LINK WITH PROVIDING UPWARD THRUST TO THE WIRE IN ITS LONG RUN SO THAT IT DOES NOT SLAG JUST LIKE THE THREAD OF A LONG FLYING KITE!
    ::)
    PRATEEK

  3. hey guys!
    the electricity meters in our homes show the monthly usage by us of active power .
    i.e V*I *cos(Q).i.e voltage*current*power factor.as power factor is less than 1,this power is less than voltage *current actual power used by us. So do we pay less than
    actual power used by us. i mean if we have only choke coils at our home we need to pay nothing. Use tubelights only !say no to bulbs.Could anyone explain the fallacy?
    prateek ;D

  4. hi there!
    i have noticed some orange coloured beautiful looking balloon like structures at  small intervals along the path of a long distance transmission lines in my country.A long distance line generally moves from 1 city to another at 33kV and passes
    through many such small balloons.can u tell me what are they?
    prateek

  5. hi kevin!
    Do all the windings have a common ground?
    With a good quality multimeter,try out checknig b/w winding-winding point and winding -ground poiint. :D
    Such transformers are used to change turns ratio and thus get varying voltages at the o/p. depending on the requirement.in your case i guess it is much simpler.
    why dont you use a t/f with constant turns ratio which gives 5V at the o/p?
    ::)
    prateek

  6. hi alun!
    you are again and again talking about the source impedance in supplying lethal current.do u think a 5V battery open cicuit without internal impedance would be
    sufficient to kill a person? ;D
    how much min voltage source can kill a person if no resistance is b/w the body and source?
    :-\

  7. hi alun!
    yes in continuation with that you might have noticee it with a 6V battery ,even if you short it with a wire u see a slight spark or somewhat heating effect and tingling sensation if you touch it to your sensative part like the tongue, in other words it is insufficient to kill you.while the current may be as high as 6A(if the resistance is 1ohm).
    Agreed!!!!!!!~!!!!!!!
    But the car example you gave,do we really have 25kV inside the car?
    why would it not kill a person?dont you think that the person who touches 25kV will
    draw a current depending upon his body resistance and will be torn to ashes?
    25kV/1M ohm=25mA sufficient to kill!!!no? ::)
    prateek

  8. hi alun!
    i apologize for using block letters. believe me i am not shouting  and i am as soft as a cotton ;D.
    can u tell me when a person gets killed by a shock, is it the high voltage which kills the person or high current.A book in physics by resnick and halliday which i studied in school shows a line man repairing a high voltage wire without switching off the power sitting in a helicopter?
    hows that? :o

  9. hi audioguru!
    i know that the limits would be crossed and it will be quite difficult to chose RC combination for the same.but what would be the problem with a 555?
    what are these CD4541 AND 4060?
    I havnt heard bout them earlier. :o
    prateek

  10. HI THERE!
    USE AN RC CIRCUIT IN SUCH A WAY THAT VOLTAGE ACROSS C RISES EXPONENTIALLY,
    FEED THE CAP VOLTAGE TO THE BASE OF A TRANSISTOR IN CUT OFF.CHOOSE R AND C SUCH THAT AFTER 15 MINS VOLTAGE ACROSS C REACHES 0.7V,THE TRANSISTOR WILL  BE DRIVEN INTO SATURATION AND CAN BE MADE TO SWITCH ON AN LED OR A RELAY IN COLLECTOR CIRCUIT.ISNT IT SIMPLE! 8)
    PRATEEK

  11. HI ALL!
    YOU MUST BE KNOWING THAT ELECTRIC POWER IS TRANSMITTED AT HIGH VOLTAGE AND CURRENT IS KEPT LOW.REASON IN SUPPORT OF THIS IS THAT HIGH CURRENT GIVES MORE I*I*R LOSS IN POWER.I WISH TO KNOW THAT WHY WONT HIGH
    V*V/R LOSS BE SIGNIFICANT HERE WHICH IS ALSO A FORMULA FOR POWER LOSS AND REMEMBER V IS IN kVs(KILO VOLTS)? ???
    PRATEEK

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