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walid

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Posts posted by walid

  1. walid
    Hi 4-1000A

    I see from what you said that the mod. index is affected by:
    1- the freq. of the modulating signal and
    2- the amplitude of the modulating signal.
    if this is the case, how can the designer control or achieve the desired mod.index he want.
    AND is it correct if we say that controlling the modulating signal amplitude by using a variable resistor can control the mod.index
    thanks.

  2. No No No Audioguru you copy and paste part of that article which i can't
    understand.
    This article looks like Text books that we learned in university, these text
    books talk about things in the other world.
    I need simply to tell me like this: "this diode is like any diode have a K & A and
    it is measure high resistance in the two directions if we are in absolutely
    dark room...."

    My question again:
    What happen when IR ray strikes this diode? Is it become short
    circuit? Are there any differences if we connect it in reverse, that is
    kathode inplace of anode and vise versa. THANKS

  3. Hi ateso8634
    if you have a 10k ohm 3 terminals trimmer  you can use it instead of the 2 terminals one.
    look at the 3 terminals trimmer's terminals, they look like a triangle there is one is far and two close,  connect (short) the far one with one of the remaining two then you have two terminals trimmer as you want.
    hope this help you. 

  4. hi 4-1000A
    your answer is excellent
    but still one point:
    in your example you calculate a mod.index 5
    i know now (after your answer) that i can control this by varying the amplitude of the modulating sig. what is the best mod.index
    if i construct a FM Tx what is the optimum mod.index

  5. To AUDIOGURU
    (1) Quote [1) I built the circuit that someone complained about, it didn't work with a new 9V battery, and also didn't work when the battery was a little old.]
    Are you mean that when the battery become less than 9V old

    (2) Quote [2) I added a low-dropout voltage regulator so that the supply voltage for the audio preamp and oscillator transistors was stable until the battery was dead]
    Are you mean by low-dropout voltage regulator that regulator small size looks like small signal transistor or what?

    (3) Quote [4) It had no treble so I added proper pre-emphasis like radio stations use.]
    please what treble and pre-emphasis?

    (4) Quote [i used good-at-high-frequencies 1000pF ceramic supply bypass caps.]
    Are these caps polyster caps or what?

    (5) Quote [i was amazed that it sounded so good. When it transmitted the sound that it picked-up from my home stereo playing an FM radio station, it sounded exactly the same as that station when received on my good car radio.]
    It seems that you put your home stereo near the Tx MIC not connecting it internally to your Tx.

  6. To Staigen

    (1)
      Quote [i usally dont calculate coils and resonanses the way you did here, i use a nomogram for this.]
      I also use MATHCAD program, i made many pages to calculate any thing like LC and others, but i do what you see because there are other people read what we are writting so I put them into my account.

    (2)
      Quote [You almost always have to tweak the coil to get the right freq in a circuit like this, or you can get a adjustable coil(usally reduce Q) or, like Audioguru did, get a trimcap] 
      I know that stretching the coil decrease L and compressing it increase L.
      I don't understand this "usally reduce Q". This you will have to explain a little bit moore
    (3)
      Quote [A 4) strays! They can easily lower the freq that amount]
      I think stray capacitances are not taken into account during calculations, and their effect can be compensated by making the cap variable or L.
    (4) Quote[This you will have to explain a little bit moore]
        you said this when I try to ask about this: I think that (not sure) only the three caps to the left with L making the LC circuit, then this group connected to the next stage (T1 and related components) through the 1nF.
        I know that if we agree about this the freq will be more than 133MHz and this will increase the problem, but i can't accept the three caps to the right to be a part of the LC circuit. please STAIGEN explain this for me. thanks.

  7. Hehe thank you staign but still........


    Still one point: I never think that the three caps to the left of the coil are in relation to the LC calculations.
    and still unbeleive thougy the serve to enlage the total C (parallel) and lower the freq.
    why not to look at these three caps with L as an independent stage that connected to the folowing (T1) through a coupling cap 1nF.
    I think that the auther think that way.
  8. I go to the 3W FM transmitter project which uses five RF chokes==>

    L2,L3,L5,L7,L9  5  6-hole Ferroxcube Wide band HF Choke (5 WDG)

    but i can't understand anything from this "6-hole Ferroxcube Wide band HF Choke (5 WDG)"
    can you explain?
    thanks

  9. Hi Staigen
    Thank you very very much for this great explaination
    Ceq = (1/(1/20pF+1/3.9pF))+15pF+(1/(1/1nF+1/20pF+1/10pF)) as you said
    Ceq =      (3.2636pF)    +15pF+      (0.8696pF)
    ceq = 19.133 pF

    Now there are three caps to the left of L and three caps to the right of it.
    To calculate L i use this equation:

                  L = 0.001 N2r2 / (228r + 254l)

    where L is the inductance in henrys,
    r is the coil radius in metres,
    l is the coil length in metres (>0.8r) and
    N is the number of turns.
    from: http://www.ee.surrey.ac.uk/Workshop/advice/coils/air_coils.html
    In FM Tx the auther give these values about the coil: phi =7.2 mm, n = 3
    so r = 7.2/2 = 3.6 mm
    0.8 r = 2.88 mm, so length of coil must be > 2.88 lets take it 3 mm ==>

    L = 0.001 (9)(1.296 E -5)/[(228 * 0.0036) + (254 * 0.003)]
    L = 1.1664 E-7          /[  0.8028      +      0.762  ]
    L = 1.1664 E-7          /[          1.5648            ]
    L = 0.7454 nH

    freq.= 1/[2 * pi * sqr(LC)]
        = 1/[2 * pi * sqr(0.7454 nH * 19.133 pF)]
        = 1/[2 * pi * sqr(1.42617 E -18)]
        = 1/[2 * pi * 1.19422 E -9]
        = 133.27 MHz which is out of the intended band (88 - 108 MHz)
    Three propabilities:
    1) a mistake in my calculations
    2) the assumption that the capacitance of the varicap is 20 pF is wrong
    3) the coil must be larger value

    Still one point: I never think that the three caps to the left of the coil are in relation to the LC calculations.
    and still unbeleive thougy the serve to enlage the total C (parallel) and lower the freq.
    why not to look at these three caps with L as an independent stage that connected to the folowing (T1) through a coupling cap 1nF.
    I think that the auther think that way.

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