charmcaster.engg
- Mar 20, 2014
- 79
- Joined
- Mar 20, 2014
- Messages
- 79
An 8 V power source is charging a capacitor. How many volts will be across the capacitor at the second time constant?
What is your attempted answer so far?An 8 V power source is charging a capacitor. How many volts will be across the capacitor at the second time constant?
I google n get, after the first interval, the capacitor voltage equals 63.2% of the battery voltage. In the second time interval, the capacitor picks up 63.2%, not of the full of battery voltage, but 63.2% of the of the difference between the starting charge(5.056) and the battery voltage(8V). I am on right track to solve the question?What is your attempted answer so far?
You sure areI google n get, after the first interval, the capacitor voltage equals 63.2% of the battery voltage. In the second time interval, the capacitor picks up 63.2%, not of the full of battery voltage, but 63.2% of the of the difference between the starting charge(5.056) and the battery voltage(8V). I am on right track to solve the question?