hi guru
You did not understand me, so I'll ask the question once again :
The 2N3904 transistor have the following char. from datasheet:
Po = 625 mW
Ic max = 200 mA
VEC max = 40 V
from that, if we have VCE = 5V, the max IC = 625m/5= 125 mA
Now if at saturation, VCE=0.4 V, then Ic max = about...