Suppose that You used a transistor 2N3904, in its datasheet I found that the Po = 625 mW; the power which this transistor can dissipate (in the form of heat) equal to 625 m Watt. Now, if we assume that VCE = 0.4 V at saturation, this transistor can pass to 1.5 ampere as Ic.
But in the datasheet Ic max = 200mA
I read from this page:
http://www.kpsec.freeuk.com/trancirc.htm
that:
The power developed in a switching transistor is very small:
In the OFF state: power = Ic × VCE, but Ic = 0, so the power is zero.
In the full ON state: power = Ic × VCE, but VCE = 0 (almost), so the power is very small.
can you explain to me to what value of Ic I can operate this transistor.
thank you.
But in the datasheet Ic max = 200mA
I read from this page:
http://www.kpsec.freeuk.com/trancirc.htm
that:
The power developed in a switching transistor is very small:
In the OFF state: power = Ic × VCE, but Ic = 0, so the power is zero.
In the full ON state: power = Ic × VCE, but VCE = 0 (almost), so the power is very small.
can you explain to me to what value of Ic I can operate this transistor.
thank you.