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  1. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    after the exel document that you spent you're time on, when you didn't have to I'm really greatful. I would like to share my findings but not in the public eye maybe we can have a private conversation!!??
  2. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    thats nice of you!! I made a discovery but I'm not ready to share it with the world untill it's perfect, but I do have to say Mr Alec_t, you have been an invaluable resource in my findings. watch this space!
  3. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    so the plot thickens!! I'll post about it sometime tomorrow :) thanks
  4. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    hmm okay I'll give it some thought!
  5. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    ok cool so then "the vertical upward force at each of those pivots must equal the weight of the (loaded) platform. So, applying just the input force as shown offers no mechanical advantage." so this is where i'm a little confused! what is Fv?? is there mechanical advantage with the scissor...
  6. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    thats exactly what I was thinking about!! so is this below not right? so the slope is 0.109 what is Fv for the if the fv is 2.57N to keep the block moving up at constant speed at the top of the scissor if the velocity is thanks
  7. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    how so? I hope you understood the previous question about the (Fh = fv) * slope
  8. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    I realize that the two lobe cam that I replace 2pi by pi I just meant is the formula still valid so you know that Force x slope x Ravg Nm. the horizontal force Fh *' slope?? or but still if the n are the stages of scissor n = 10 so, (10 * fv = Fv ) and have 10% slope, Fh is 10% of Fv, then Fh...
  9. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    the numbers work out better with this equation
  10. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    Is this still vaid?? you could consider the spiral has an average radius Ravg half way between the minimum and maximum radii Rmin, Rmax. The spiral length would then be 2 x pi x Ravg. Over that length the cam-follower moves a vertical distance Rmax - Rmin. So, the average slope is...
  11. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    the energy of the block before it drops is3.392920066J 3.392920066J / 1.319568915m = 2.57123N force needed to keep moving at constant velocity = 2.57123N 2.57123N / 9.80665 =mass of 0.2622kg accelerating force =0.2622kg * 3.3m/s^2 = 0.86526N But this is counter intuitive because the...
  12. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    I think I am missing something because the force that will only be overcoming the weight and the acceleration due to gravity (2.5713N) that keeps it as that same velocityis MORE than the accelerating force of 0.865N where as it should be less
  13. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    so f = ma 0.2622kg * 3.3m/s^2 = fv = 0.865N and so because slope is 10% and 10 stages of scissor Fh = s% of Fv Fh = 0.865N!! this is accounting for the face that 3.3m/s^2 is acceleration and for the force we need to multiply by the mass 0.2622kg
  14. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    do you get what I mean? is that correct?? thanks
  15. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    I meant in all cases that there are 10 stages and 10% slope that = to 1 no matter the force required at the top of the cam follower the Fh will equal fv
  16. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    okay yes I get that a = delta v / t and am glad you included that information but still if the n are the stages of scissor n = 10 so, (10 * fv = Fv ) and have 10% slope, Fh is 10% of Fv, then Fh must equal to the fv in all cases?!? thanks because the 10 * 10% = 1 so that's 1 *fv or just fv is...
  17. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    fv = Fh since the scissors have 10 levels and the slope remains 10% so no matter the the force required at the top, Fh will be equal to fv!! correct??
  18. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    because if it's Fv then Fh will be s% of Fv = 13.10665N * 0.1 = 1.311N BUT thats less than the 2.5713N (0.2622kg * 9.80665m/s^2) so the 13.10665 must be the Fh Am I missing something?? thanks Fh = fv = 13.106N for 10% of the time! remaining 90% = 2.571N
  19. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    yes sorry about that I wasn't thinking about that I was thinking about the formula You want the weight to rise at constant velocity; but when the weight falls to its lowest point it instantly has zero velocity and then has to reverse to have a positive (upward) velocity. Let's assume that for...
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