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  1. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    okay so i have the force Fh of 1.696N what then is the mass and acceleration, sorry if this sounds stupid but it requires less force to lift the weight of 1.1528kg
  2. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    "do I need to add 1g?" I think not because the starting point of the 11.3097N has gravity in it intrinsically No additional gravitational force: If the 11 Newtons downward already includes gravitational effects, then you need an equal and opposite 11 Newtons upward to balance it. and so the...
  3. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    so been wondering for a while now Re-thinking the maximum torque needed, it won't occur at the maximum radius of the cam as assumed so far; it will actually be at the minimum radius by my reckoning, for the following reason. is the force dependent of the speed of the cam?? I want it to turn...
  4. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    ok so is that Rmin 26.8309cm and Rmax 36.8309cm I put those figures into the equation and sure enough equals 0.05 (or 5%) thanks
  5. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    hmm I thought about that (the two variables) ok I'll think about it for a bit I want it to work out that the slope = 5% but also want the Rmin and Rmax to be a difference of 10cm, do you get my problem? thanks is it just trial and error?
  6. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    can I rearrange this formula for 5% slope?? average radius Ravg half way between the minimum and maximum radii Rmin, Rmax. the smaller the lower radius the better because lower radius = lowers required torque!
  7. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    so now I'm thinking 3.3929J / 0.3m (height) = 11.3097N approx 1.1528kg, and have a cam that varies with 1 lobe 10cm drop off (need to design the cam so that the slope is 5%) and have the scissor have only 3 levels, this way Fv will be 3*f and then so Fv = 3 * 11.3097 = 33.9292, and the Hf will...
  8. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    sorry now I'm going the other way heavier weight, less height, so less stage of scissor and for a cam profile of 5% slope!! hope that you can read it now!!
  9. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    weather the distance of the arc of the lever is lifted 1.319468915m and 2.571428573N downwards or arc of 13.57168026m and 0.25N the energy is = to 3.392920066J fo acceleration of 0.05rad/s^2 and inertia of 10.8kgm^2
  10. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    if the force downawrd is 0.25N (25gram 0.02549290532kg) it needs to lift 13.57168026 meters It just makes sence that the moving mass of 40kg 10.8kgm^2 can lift the 25 gram weight 13.57168026m easily given the right mechanism what do you guys think if it hits with impact to "shoot" it up and not...
  11. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    so whatever I do the energy to move the 10.8km^2 inertia flywheel at 0.05rad/s^2 that weights approx 40kg in the ring format the energy is 3.392920066J but if I have (1 newton then that weighs approx 102grams) J/N = meter (high) then the height it needs to lift up is 3.392920066m and the lever...
  12. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    ok cool so its 31.16883117N cool thanks
  13. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    can anyone have a crack? I'd prefer a formula though because I want to experiment with different sizes of gear 5! thanks
  14. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    thanks Mr Bertus! that info is good but was kind of asking for the simplistic answer or formula to work out tangential force on the input fifth gear if the out put on gear 1 is 5.142857143 with this coumpound gear train the gear 5 turns 1/4 of the output!
  15. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    anyone?
  16. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    trying to work out the force at gear 5 (input) can't get an answer from chatgpt, it's giving a different answer every time
  17. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    If you do happen to have any other questions fire away, I'm ready!
  18. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    F off did you get chatgpt to draw that for you :)
  19. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    I think you mean trouser pockets still don't know what the scissor has to do with windmills
  20. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    quid skrillar moola wonga p's coinage doe paper etc
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